Is 2x x^2 ? (1) 0 ≤ x^2 ≤ 9 (2) x is an odd prime integer

Question

Is  2x > x^2  ?

(1)  0 ≤ x^2 ≤ 9

(2) x is an odd prime integer.

ProKiller · Answer

Stmt 1 -
If x = 1/2, then answer is YES.
If x = 2, then answer is NO.
Not sufficient.

Stmt 3 -
First odd prime integer is 3 - NO
Next 5 - NO
.... and NO for all.
Sufficient.

Answer - B.

harshtandel838 · Answer

The inequality given is complex, we need to break it into simple one.

2x > x^2
2x - x^2 > 0
x ( 2 - x) > 0
For the above condition, both x and 2-x should be greater than 0.
i.e x > 0 AND 2-x > 0
i.e 0 < x < 2

Now solving the statements;

Clearly, statement 1 is INSUFFICIENT

Statement 2 says, x is an odd prime integer. Here we know that the value of x will not be in the range 0 < x < 2
Thus, SUFFICIENT

Hence, answer is B

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speedrevision37 · Answer

2x > x^2 x^2-2x<0 x(x-2)<0 02 so sufficient Ans B

IanStewart · Answer

For Statement 1, if x = 1, 2x > x^2 is true, and if x = 3 it is not. So Statement 1 is not sufficient.

Using Statement 2, if x is prime then x is positive. So we can rewrite the question, by dividing by x on both sides, and since x is positive we know we won't need to reverse the inequality. So the question "Is 2x > x^2" becomes "Is 2 > x?" and if x is an odd prime, clearly x is not less than 2, so we can be sure the answer to the question is 'no', and Statement 2 is sufficient alone.

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Is 2x > x^2 ? (1) 0 ≤ x^2 ≤ 9 (2) x is an odd prime integer

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