Bunuel
The product of digits of a positive three-digit integer k is 120. Is k a multiple of 5?
(1) k is a multiple of 3.
(2) If we switch any digits in k, it will decrease.
Given: The product of digits of a positive three-digit integer k is 120. Since there aren't that many three digit integers that satisfy this information, I find it useful to take the time out front to identify the possible cases.
First recognize that k = (2)(2)(2)(3)(5)
So, the three digits could be
4, 5 and 6 OR
3, 5 and 8.
Target question: Is k a multiple of 5? Statement 1: k is a multiple of 3 If k is a multiple of 3, then the sum of the digits of k must be divisible by 3
4 + 5 + 6 =
15, which is divisible by 3, so the three digits of k could be
4, 5 and 6 3 + 5 + 8 =
16, which is NOT divisible by 3, so the three digits of k can't be
3, 5 and 8 So, it could be the case that k = 465, in which case
k is a multiple of 5.It could also be the case that k = 456, in which case
k is a NOT multiple of 5.Since we can’t answer the
target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: If we switch any digits in k, it will decrease.This means the digits of k are such that the value of k is
maximized.
Since the three digits could be
4, 5 and 6 OR
3, 5 and 8, there are two possible values of k:
k = 654 or
k = 853 If k = 654, then
k is NOT a multiple of 5.If k = 853, then
k is NOT a multiple of 5.This means there is only one possible answer to be target question.
Since we can answer the
target question with certainty, statement 2 is SUFFICIENT
Answer: B
Cheers,
Brent