Bunuel
Square G has sides of length 4 inches. Is the area of Square H exactly one half the area of Square G?
(1) The length of the diagonal of Square H equals the length of one side of Square G.
(2) The perimeter of Square H is twice the length of the diagonal of Square G
Given: Square G has sides of length 4 inches. Area of square G = (side)² = 4² =
16Target question: Is the area of Square H exactly one half the area of Square G?This is a good candidate for
rephrasing the target question.
Area of square G =
16So, the target question is asking how's the weather the area of Square H = 8 (which is half of
16)
If the area of Square H were 8, then each side of the square would have length √8
REPHRASED target question: Does each side of Square H have length √8?Aside: the video below has tips on rephrasing the target question Statement 1: The length of the diagonal of Square H equals the length of one side of Square G. In other words, the diagonal of Square H has length 4, which means we have the following:

When we apply the Pythagorean theorem we get, x² + x² = 4²
Simplify: 2x² = 16
Divide both sides by 2 to get: x² = 8
Solve:
x = √8 So, the answer to the REPHRASED target question is
YES, each side of Square H has length √8Statement 1 is SUFFICIENT
Statement 2: The perimeter of Square H is twice the length of the diagonal of Square GHere's Square G:

When we apply the Pythagorean theorem we get, 4² + 4² = d²
Simplify: 16 + 16 = d²
Simplify: 32 = d²
Solve: d = √32 = 2√8
(notice that I didn't completely simplify √32 to get 4√2. You'll see why shortly)This means the
perimeter of Square H = 2(2√8) = 4√8
So, each
side of Square H has length √8
The answer to the REPHRASED target question is
YES, each side of Square H has length √8Statement 2 is SUFFICIENT
Answer: D
VIDEO ON REPHRASING THE TARGET QUESTION: