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Bunuel
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From the 1st statement:-
The units digit of x^2=4 which implies that the units digit of x could be either 2 or 8.
Let's assume x=12, then 12*12=144 ;
Let's assume x=28 then, 28*28=784
Since this presents two different values for the units digit of x, this is insufficient.

From the 2nd statement:-
The units digit of (x+1)^2=1 which implies that the units digit of x+1 could be either 1 or 9.
Let's assume (x+1)=11, then 11*11=121 ;
Let's assume (x+1)=19 then, 19*19=361.
If the units digit of (x+1) is 1 then the units digit of x=0; For e.g 11-1=10 ;
If the units digit of (x+1) is 9 then the units digit of x=8 ; For e.g 19-1=18.
Since we have two different values for the units digit of x, this is insufficient.

Now if we combine both statements, the only value for the units digit of x that satisfies both is 8.Therefore,both statements combined are sufficient to determine the units digit of x.

IMO C.
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Bunuel
What is the units digit of positive integer x?

(1) Units digit of x^2 = 4

(2) Units digit of (x+1)^2 = 1


(1) Units digit of x^2 = 4
Unit digit of X can be 2 or 8
Not Sufficient.

(2) Units digit of (x+1)^2 = 1
We can get square of a unit digit 1 in only two cases 1 and 9
& for (x+1)^2 x has to be 0 or 8 but x cannot be 0 since x is +ve.
So x has to be 8.
Sufficient.

B is the answer.
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Bunuel
What is the units digit of positive integer x?

(1) Units digit of x^2 = 4

(2) Units digit of (x+1)^2 = 1


(1) Units digit of \(x^2 = 4\)

\(x \) could be of the form _ _ 2 i.e. ending with \(2\)
\(x \) could be of the form _ _ 8 i.e. ending with \(8\)

INSUFF.

(2) Units digit of \((x+1)^2 = 1\)

\(x \) could be of the form _ _ \(0\) i.e. ending with \(0\)
\(x\) could be of the form _ _ \(8\) i.e. ending with \(8\)

INSUFF.

1+2

\(x\) is of the form _ _ \(8 \)

SUFF.

Ans C

Hope it's clear.
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Lets try to get a definite answer to the question stem by using these statements given.

(1) Units digit of \( x^2\) = 4

From St 1. we can conclude that unit digit of x could be either 2 or 8.

Since we have 2 possible answers, St 1 alone is not sufficient.


(2) Units digit of \((x+1)^2 \)= 1

From St 2, we can conclude that the unit digit of x+1 should be either 1 or 9 . i.e the unit digit of x should be either 0 or 8.

Since there are 2 possible answers, Statement 2 alone is not sufficient .

Combining St 1 and St 2 , only possible unit digit of x that satisfies both the statements is 8.

Since we get a unique answer to the question stem,Option C is the correct answer.

Thanks,
Clifin J Francis.
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