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19 Jan 2022, 09:30
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
53% (01:44) correct
47%
(01:41)
wrong
based on 180
sessions
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A box contains balls that are either yellow, black or brown in color. One ball is chosen at random from the box. Is the probability that the chosen ball is black greater than 3/4?
(1) The probability that the chosen ball is not brown is less than 2/5
(2) The probability that the chosen ball is not black is greater than 3/5
(1) The probability that the chosen ball is not brown is less than 2/5
(2) The probability that the chosen ball is not black is greater than 3/5
19 Jan 2022, 14:51
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Bunuel
Breaking Down the Info:
The balls must be one of the three given colors, so we have \(Pr(Yellow) + Pr(Black) + Pr(Brown) = 100\%\) by default.
Statement 1 Alone:
We can read this as "the probability that the chosen ball is yellow or black is less than \(\frac{2}{5}\)." Then the probability of having a black ball is less than \(\frac{2}{5} = 40\%\), which cannot be greater than \(\frac{3}{4}\). Thus statement 1 alone is sufficient.
Statement 2 Alone:
We can translate this to "the probability that the chosen ball is black is less than \(\frac{2}{5}\)." Thus the probability of having a black ball cannot be greater than \(\frac{3}{4}\). Thus statement 2 alone is sufficient.
Answer: D
21 Jan 2022, 02:07
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Hey JerryAtDreamScore,
Can you please explain the statement one a little more elaboratly, i think im not able to understand what the question is asking
Can you please explain the statement one a little more elaboratly, i think im not able to understand what the question is asking
