Bunuel
Bunuel
Is \((\frac{a}{p})(p^2+r^2+s^2)=ap+br+cs\)?
(1) \(\frac{c}{s}=\frac{a}{p}\)
(2) \(\frac{a}{p}=\frac{b}{r}\)
Bumping!!! Knockout this one and get KUDOS for a correct solution!!!
Simplyfing the equation in stem we get is ap + ar²/p + as²/p = ap + br + cs ? Cancelling out ap from both sides I get ar²/p + as²/p = br + cs?
(i) c/s = a/p substituting this in left hand side of the equation I get cr²/s + cs = br + csCancelling out cs from both sides, I get cr²/s = br
(Assuming r is non-zero, invalid assumption, but for what it's worth, let's cancel r from both sides)
We get cr = b and we have no reasons to believe this will hold true because we don't have any relations given between the three quantities c, r, and b.
Therefore, statement 1 is insufficient, eliminate options A and D.(ii) a/p = b/r substituting this in left hand side of the equation I get br²/r + bs²/r = br + csCancelling out br from both sides, I get bs²/r = cs
(Assuming s is non-zero, invalid assumption, but for what it's worth, let's cancel s from both sides)
We get bs = c and we have no reasons to believe this will hold true because we don't have any relations given between the three quantities b, s, and c.
Therefore, statement 2 is insufficient, eliminate option B.Combining both the statements, I get a/p = c/s = b/rPutting this back in the left hand side of the equation I get
br²/r + cs²/s = br + cs or
br + cs = br + cs
Which is perfect!
Hence, using both the statements together, we can answer this question, option C.Posted from my mobile device