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27 Apr 2022, 01:30
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
55% (02:29) correct
45%
(02:52)
wrong
based on 93
sessions
History
Date
Time
Result
Not Attempted Yet
If positive integer k is a multiple of 5, what is the remainder when k is divided by 6?
(1) When k is divided by 4, the remainder is 3.
(2) When k is divided by 12, the remainder is 3.
(1) When k is divided by 4, the remainder is 3.
(2) When k is divided by 12, the remainder is 3.
27 Apr 2022, 04:49
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Pre-thinking
Value of k: 5, 10, 15, 20, 25, 30, 35...
Remainder: 5, 4, 3, 2, 1, 0, 5...
Note the pattern of 5, 4, 3, 2, 1, 0 for 6 consecutive numbers (every 30).
(1) Only
when k is 15, the remainder when k is divided by 6 is 3
when k is 15+20 = 35, the remainder when k is divided by 6 is 5. (20 is LCM of 5 and 4)
Not sufficient.
(2) Only
when k is 15, the remainder when k is divided by 6 is 3.
when k is 15+60=75, the remainder when k is divided by 6 is 3. (60 is LCM of 5 and 12).
The remainder of 3 (when k is divided by 6) for other k because 60 is double 30.
Sufficient.
The answer is thus (B).
Value of k: 5, 10, 15, 20, 25, 30, 35...
Remainder: 5, 4, 3, 2, 1, 0, 5...
Note the pattern of 5, 4, 3, 2, 1, 0 for 6 consecutive numbers (every 30).
(1) Only
when k is 15, the remainder when k is divided by 6 is 3
when k is 15+20 = 35, the remainder when k is divided by 6 is 5. (20 is LCM of 5 and 4)
Not sufficient.
(2) Only
when k is 15, the remainder when k is divided by 6 is 3.
when k is 15+60=75, the remainder when k is divided by 6 is 3. (60 is LCM of 5 and 12).
The remainder of 3 (when k is divided by 6) for other k because 60 is double 30.
Sufficient.
The answer is thus (B).
27 Apr 2022, 06:00
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Ans: B
k is multiple of 5
1)k=4a+3...k can be 15 35 etc 15%6=3 35%6=5 diff values not sufficient
2)k=12b+3
k%6=12b%6+3%6=0+3=3
sufficient
k is multiple of 5
1)k=4a+3...k can be 15 35 etc 15%6=3 35%6=5 diff values not sufficient
2)k=12b+3
k%6=12b%6+3%6=0+3=3
sufficient
