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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
48% (01:09) correct
52%
(01:17)
wrong
based on 66
sessions
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If neither \(x\) nor \(y\) is equal to 0, is \(3x−2y=0\)?
(1) \(27x^3−8y^3=0\)
(2) \(9x^2−4y^2=0\)
Are You Up For the Challenge: 700 Level Questions
(1) \(27x^3−8y^3=0\)
(2) \(9x^2−4y^2=0\)
Are You Up For the Challenge: 700 Level Questions
21 May 2022, 13:03
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(1)
\(27x^3 - 8y^3 = 0\)
Taking the cube root of the above equation will give: \(3x - 2y = 0\)
SUFFICIENT
(2)
\(9x^2 - 4y^2 = 0\)
Taking the square root of the above equation does not provide a concrete answer, as one cannot be certain whether \(x\) and \(y\) are positive or negative.
For instances plugging in \(x = 2\) and \(y = 3\) works for \(9x^2 - 4y^2 = 0\). Which then means that the statement \(3x - 2y = 0\) will hold true.
However, \(x = -2\) and \(y = -3\) too will hold for \(9x^2 - 4y^2 = 0\), but plugging those values into \(3x - 2y\) will give \(3(-2) - 2(-3) = -12\).
INSUFFICIENT
Answer A
\(27x^3 - 8y^3 = 0\)
Taking the cube root of the above equation will give: \(3x - 2y = 0\)
SUFFICIENT
(2)
\(9x^2 - 4y^2 = 0\)
Taking the square root of the above equation does not provide a concrete answer, as one cannot be certain whether \(x\) and \(y\) are positive or negative.
For instances plugging in \(x = 2\) and \(y = 3\) works for \(9x^2 - 4y^2 = 0\). Which then means that the statement \(3x - 2y = 0\) will hold true.
However, \(x = -2\) and \(y = -3\) too will hold for \(9x^2 - 4y^2 = 0\), but plugging those values into \(3x - 2y\) will give \(3(-2) - 2(-3) = -12\).
INSUFFICIENT
Answer A
