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Please correct me -

S1: x > -3
so x can be -1, -2, 0, 1, etc.
Not sufficient

S2: p = 3-q
or, p + q = 3

Substituting in the original equation:
p + q > 6x
3 > 6x
0.5 >x
Hence, x < 0.5
Clearly insufficient

There'll be multiple values. Shouldn't the ans be E?

Bunuel
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summerbummer
Please correct me -

S1: x > -3
so x can be -1, -2, 0, 1, etc.
Not sufficient

S2: p = 3-q
or, p + q = 3

Substituting in the original equation:
p + q > 6x
3 > 6x
0.5 >x
Hence, x < 0.5
Clearly insufficient

There'll be multiple values. Shouldn't the ans be E?

Bunuel

summerbummer You're correct that you're left with an inequality and that multiple values are possible for x.

However, the wording of the question is a bit unusual: it asks "for which VALUES of x", plural. So, it is actually asking us for an inequality, not an individual value.

Also, in your work for statement 2, it looks like you forgot to include the 4x on the left side of the equation, but this doesn't affect the answer here on DS.
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