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Statement 1

\(120 = 5 * 3 * 2^3\)

This indicates that out of the four consecutive numbers, one number should be a multiple of 5.

The number 5 can come in any position, i.e. the series can either start with 5 or end with 5 or 5 can occupy any of the two middle positions.

Ex.

5 6 7 8
4 5 6 7
3 4 5 6
2 3 4 5

Alternatively, we can also have 10

10 11 12 13
09 10 11 12
08 09 10 11
07 08 09 10

To ascertain "Is the sum of four consecutive integers a multiple of 10 ?", we only care about the last digit. Hence in both the sets we see that the sum of the last digits is not a multiple of 10.

Hence this statement is enough to ascertain that the sum is not a multiple of 120

Statement 2

The analysis to this is similar to what we have already done. Infact, its a subset -

The number can have the unit digit in any one of the below series -

5 6 7 8
4 5 6 7
3 4 5 6
2 3 4 5

As discussed in statement 1 , the sum of the unit digits does not add to be a multiple of 10, hence this statement is also sufficient

IMO D
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Is the sum of four consecutive integers a multiple of 10 ?

(1) The product of the four integers is a multiple of 120.
If we go through the product of four numbers we get a pattern and this pattern continues
2,3,4,5 --> Product multiple of 120 --- Sum not multiple of 10
3,4,5,6 --> Product multiple of 120 --- Sum not multiple of 10
4,5,6,7 --> Product multiple of 120 --- Sum not multiple of 10
5,6,7,8 --> Product multiple of 120 --- Sum not multiple of 10
6,7,8,9 --> Product is NOT multiple of 120 --- Sum IS multiple of 10
7,8,9,10--> Product multiple of 120 --- Sum not multiple of 10
8,9,10,11--> Product multiple of 120 --- Sum not multiple of 10
9,10,11,12 --> Product multiple of 120 --- Sum not multiple of 10
10,11,12,13 --> Product multiple of 120 --- Sum not multiple of 10
11,12,13,14 --> Product is NOT multiple of 120 --- Sum IS multiple of 10
12,13,14,15 --> Product multiple of 120 --- Sum not multiple of 10
13,14,15,16 --> Product multiple of 120 --- Sum not multiple of 10
14,15,16,17 --> Product multiple of 120 --- Sum not multiple of 10
15,16,17,18 --> Product multiple of 120 --- Sum not multiple of 10
16,17,18,19 --> Product is NOT multiple of 120 --- Sum IS multiple of 10

Answer is NO. Sufficient

(2) The product of the unit digits of the four integers is a multiple of 120.
Taking the same pattern from above we get
0,1,2,3 --> Product multiple of 120 --- Sum not multiple of 10
2,3,4,5 --> Product multiple of 120 --- Sum not multiple of 10
3,4,5,6 --> Product multiple of 120 --- Sum not multiple of 10
4,5,6,7 --> Product multiple of 120 --- Sum not multiple of 10
5,6,7,8 --> Product multiple of 120 --- Sum not multiple of 10
7,8,9,0--> Product multiple of 120 --- Sum not multiple of 10
8,9,0,1--> Product multiple of 120 --- Sum not multiple of 10
9,0,1,2 --> Product multiple of 120 --- Sum not multiple of 10

Answer is NO. Sufficient

IMHO Option D
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