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101Gmatguru
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Bunuel
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101Gmatguru
Bunuel So for any inequality in the form of |n+1| > 0, it is implied that n is not equal to -1

Similarly, for |n+3| > 0, it is implied that n is not equal to -3.

Also, for |n-3| > 0, is it implied that n is not equal to 3?

Yes, you are right in making this implication. And if you wonder how come we came to this, we can arrive using the property of modulus and inequality
Let us see how

|n+1| > 0

So entire expression of modulus is always greater than 0 but what's inside the modulus can be both greater than 0 or less than 0

If expression inside modulus is > 0, then it remains as it is, else it changes signs to negative
For eg. If x=5, |x| = x but if x=-5, |x| = -x

Similarly let us test both cases

Case 1: n+1 is positive
n + 1 > 0
n > -1

Case 2: n+1 is negative
-n - 1 > 0
n < - 1

So entire range of n is either greater than -1 or less than -1
Which implies that n is not equal to -1

Posted from my mobile device
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