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Updated on: 29 Sep 2022, 10:33
Originally posted by BrentGMATPrepNow on 29 Sep 2022, 06:42.
Last edited by BrentGMATPrepNow on 29 Sep 2022, 10:33, edited 1 time in total.
Last edited by BrentGMATPrepNow on 29 Sep 2022, 10:33, edited 1 time in total.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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If |2x| = |3y|, what is the value of |2x + 3y|?
(1) 3x – 2y = 10
(2) xy < 0
(1) 3x – 2y = 10
(2) xy < 0
Archit3110
Major Poster
Updated on: 29 Sep 2022, 10:41
Originally posted by Archit3110 on 29 Sep 2022, 10:03.
Last edited by Archit3110 on 29 Sep 2022, 10:41, edited 1 time in total.
Last edited by Archit3110 on 29 Sep 2022, 10:41, edited 1 time in total.
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given
|2x| = |3y|
possible for all +ve & -ve multiples of 6 on LHS & RHS as its product
x,y : (0,0 )( 3,2)( 6,4) ( 9,6) ( 12,8) ( 15,10) so on
#1
3x – 2y = 10
possible at x,y ( 6,4)
or in fractions if x 30/13 and y -20/13
insufficient
#2
xy < 0 and given condition |2x| = |3y|
x,y ( -6,4) or ( 6,-4) and any pair of opposite sign as discussed above to meet condition
value of target l2x+3yl would always be 0
OPTION B is sufficient
|2x| = |3y|
possible for all +ve & -ve multiples of 6 on LHS & RHS as its product
x,y : (0,0 )( 3,2)( 6,4) ( 9,6) ( 12,8) ( 15,10) so on
#1
3x – 2y = 10
possible at x,y ( 6,4)
or in fractions if x 30/13 and y -20/13
insufficient
#2
xy < 0 and given condition |2x| = |3y|
x,y ( -6,4) or ( 6,-4) and any pair of opposite sign as discussed above to meet condition
value of target l2x+3yl would always be 0
OPTION B is sufficient
BrentGMATPrepNow
29 Sep 2022, 10:17
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Archit3110
There's a second solution, where x and y have opposite signs, to Statement 1 (it can be true that x = 30/13 and y = -20/13), so the two statements are consistent (and the answer is B, not D).
