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gmatphobia ,
Bunuel
If we solve Statement 1 in the following way , then we get only one value.

STATEMENT 1 .

(a+b)^2 = 4 .
Taking square root both sides.

a+b = \sqrt{4}
In GMAT square root has just the positive value.

Hence,
a+b = 2

So answer choice C is the answer.

Regards
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GMATTarget720plus
gmatphobia ,
Bunuel
If we solve Statement 1 in the following way , then we get only one value.

STATEMENT 1 .

(a+b)^2 = 4 .
Taking square root both sides.

a+b = \sqrt{4}
In GMAT square root has just the positive value.

Hence,
a+b = 2

So answer choice C is the answer.

Regards

When the GMAT (and generally in math) provides the square root sign for an even root, such as a square root, fourth root, etc. then the only accepted answer is the non-negative root. That is:

\(\sqrt{9} = 3\), NOT +3 or -3;
\(\sqrt[4]{16} = 2\), NOT +2 or -2;

Notice that in contrast, the equation \(x^2 = 9\) has TWO solutions, +3 and -3. Because \(x^2 = 9\) means that \(x =-\sqrt{9}=-3\) or \(x=\sqrt{9}=3\).

Hope it helps.
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