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Bunuel
If k is a positive integer whose only prime factors are 2 and 5, is k divisible by 20?

(1) k is a multiple of 16
(2) k has 6 factors

If k is a positive integer whose only prime factors are 2 and 5, is k divisible by 20?

k is a positive integer whose only prime factors are 2 and 5: \(k=2^x*5^y\), where \(x\geq{1}\) and \(y\geq{1}\) (notice that the number of factors of k would be (x + 1)(y + 1)). Also notice that k will be divisible by \(20 = 2^2*5\) if \(x\geq{2}\) and \(y\geq{1}\) (this condition is already satoisfied from the stem). So, the question basically asks whether \(x\geq{2}\).

(1) k is a multiple of 16. 16 = 2^4, hence this statement implies that \(x \geq{4}\). Sufficient.

(2) k has 6 factors --> this means that (x + 1)(y + 1) = 6. If x = 2 and y = 1, then the answer will be YES but if x = 1 and y = 2, then the answer will be NO. Not sufficient.

Answer: A.

Hope it's clear.
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