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a. Since I=II=III, then the area for all three triangles is 90.
Since II=I, which is half of the length of AB, then II is also half of the length of DC. This means that IV and V combined are also half of the length of DC. Thus, 90+30=120. SUFFICIENT

b. Since IV and V combined are half of the length of DC, then II is also half of the length of DC. II, IV and V combined would total an area of 60. Since II=I=III, then I and III combined would total an area of 60. 60+60=120. SUFFICIENT.
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