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23 Jan 2023, 02:30
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
65% (02:06) correct
35%
(01:59)
wrong
based on 77
sessions
History
Date
Time
Result
Not Attempted Yet
A marzipan factory has two machines producing marzipan. Every day, the two machines operate constantly from 08:00 to 18:00, and produce together N kg of marzipan. What percent of the total amount of marzipan produced by machines W and D together was produced by machine W?
(1) Working alone, it takes machine W twenty five hours to produce (N/2) kg of marzipan.
(2) Machine W alone produces N/2 kg of marzipan in double the time it takes machine D alone to produce N kg of marzipan.
700+ question.
(1) Working alone, it takes machine W twenty five hours to produce (N/2) kg of marzipan.
(2) Machine W alone produces N/2 kg of marzipan in double the time it takes machine D alone to produce N kg of marzipan.
700+ question.
23 Jan 2023, 12:16
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Bunuel
Hours worked by both the machines = 1800 - 0800 = 10 hours
Statement 1
(1) Working alone, it takes machine W twenty five hours to produce (N/2) kg of marzipan.
To produce N/2 kgs of marzipan, machine W takes 25 hours.
To produce N kgs of marzipan, the machine will take double the time, i.e. 50 hours.
Let the time taken to produce N kgs of marzipan by machine D = d
Time taken together = 50d/ 50 + d
\(10 = \frac{50d}{ 50 + d}\)
We can find the value of d. Once we obtain the value of d, we can find the efficiency ratio. The output will depend on the efficiency of the machines.
As in any DS question - we don't actually need to find the value. We need to know if using the given statement(s) is it possible to find the value.
In this case, yes we can find the value.
Statement 1 is sufficient
Statement 2
(2) Machine W alone produces N/2 kg of marzipan in double the time it takes machine D alone to produce N kg of marzipan.
To produce N/2 kgs of marzipan it takes machine W double the time it takes machine D to produce N kgs of marzipan. So to produce N kgs of marzipan machine W will take four times the time machine D takes to produce N kgs of marzipan.
Therefore machine W is four times slower than machine D.
Using the efficiency ratio we can get the percent of the total amount of marzipan produced by machines W and D together was produced by machine W.
This statement is also sufficient.
Option D
28 Jul 2025, 09:43
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