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Bunuel
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The answer should be E as root(20) can be -4.47 as well. We cannot neglect that value.

First of all, (1) says that p is an integer, so it cannot be -4.47. p also cannot be negative since (2) says that √20 < p < 16/3. Remember that the square root sign for an even root, such as a square root, fourth root, ... cannot given negative result , hence √20 is positive only (approximately 4.47).
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I still don't get why Root(20) can't be negative. (-4.47)^2 is also equal to 20. Also if we solve x^2 = 20 we get 2 real values of x (4.47 and -4.47) Now if we consider integers between -4.47 and 5.33 , there can be many values right??
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I still don't get why Root(20) can't be negative. (-4.47)^2 is also equal to 20. Also if we solve x^2 = 20 we get 2 real values of x (4.47 and -4.47) Now if we consider integers between -4.47 and 5.33 , there can be many values right??

Mathematically, \(\sqrt{...}\) is the square root sign, a function (called the principal square root function), which cannot give negative result. So, this sign (\(\sqrt{...}\)) always means non-negative square root.


The graph of the function f(x) = √x

Notice that it's defined for non-negative numbers and is producing non-negative results.

TO SUMMARIZE:
When the GMAT (and generally in math) provides the square root sign for an even root, such as a square root, fourth root, etc. then the only accepted answer is the non-negative root. That is:

\(\sqrt{9} = 3\), NOT +3 or -3;
\(\sqrt[4]{16} = 2\), NOT +2 or -2;

Notice that in contrast, the equation \(x^2 = 9\) has TWO solutions, +3 and -3. Because \(x^2 = 9\) means that \(x =-\sqrt{9}=-3\) or \(x=\sqrt{9}=3\).

Hope it helps.
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I still don't get why Root(20) can't be negative. (-4.47)^2 is also equal to 20. Also if we solve x^2 = 20 we get 2 real values of x (4.47 and -4.47) Now if we consider integers between -4.47 and 5.33 , there can be many values right??

For GMAT just remember that even number square root is ALWAYS POSITIVE
=> sqrt 9 = 3 only
Or in general
Sqrtx^2 = |x| = x if x>=0
= -x if x<=0

Another way to think about why square root is always positive is ...
when we do prime factorization do we get negative factors? NO.
Prime factors are always positive. So, in similar lines, square root is always positive.


Similarly if it is odd root
(-27)^(1/3) =-3 only, or
(8)^(1/3) = 2 only
i.e., odd root returns the base number.


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