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Bunuel Am I correct ?
given |z|<6
-6<z<6

1.
|z-2|>3
z-2>3
z>5

-z+2>3
-z>1
z<-1
NS

2.
|z|=2
therefore
z=-2,2

NS

combining 1 and 2 & |Z|<6
NS

Answer E
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Bunuel Am I correct ?
given |z|<6
-6<z<6

1.
|z-2|>3
z-2>3
z>5

-z+2>3
-z>1
z<-1
NS

2.
|z|=2
therefore
z=-2,2

NS

combining 1 and 2 & |Z|<6
NS

Answer E

The OA is neither C, nor E. :dontknow:
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Bunuel Am I correct ?
given |z|<6
-6<z<6

1.
|z-2|>3
z-2>3
z>5

-z+2>3
-z>1
z<-1
NS

2.
|z|=2
therefore
z=-2,2

NS

combining 1 and 2 & |Z|<6
NS

Answer E

The OA is neither C, nor E. :dontknow:


Sorry my bad,
In statement 1
z>5 wont be possible , because z is an integer
So answer will be option A
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Bunuel
Nabneet
Bunuel Am I correct ?
given |z|<6
-6<z<6

1.
|z-2|>3
z-2>3
z>5

-z+2>3
-z>1
z<-1
NS

2.
|z|=2
therefore
z=-2,2

NS

combining 1 and 2 & |Z|<6
NS

Answer E

The OA is neither C, nor E. :dontknow:


Sorry my bad,
In statement 1
z>5 wont be possible , because z is an integer
So answer will be option A

z is an integer such that |z| < 6. Is z positive?

Since z is an integer and -6 < z < 6, then z can be -5, -4, -3, ..., 5.

(1) |z - 2| > 3

z - 2 > 3 or z - 2 < -3
z > 5 or z < -1.

z > 5 cannot be true since z can be -5, -4, -3, ..., 5, therefore, z < -1 and the answer to the question is NO, z is not positive.

Sufficient.

(2) |z| = 2.

z = 2 or z = -2, which is clearly not sufficient to say whether z is positive.

Answer: A.
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[/quote]

You correctly identified that from (1) we get z < -1 or z > 5. What would be the possible value of z if we also take into the account that |z| < 6 ?[/quote]

I think this one must be E and here its why (UPDATE: I founded my error, A its the correct answser):

''z is an integer such that |z| < 6. Is z positive?
(1) |z - 2| > 3
(2) |z| = 2 ''

First I wanna say that I understood the question as "can we be sure that z its a positive number?" instead "its possible to z be a positive number?"

The text says: ''z is an integer such that |z| < 6.'', so we know that z can assume the values: {-6, -5, -4....5, 6}
Here's the error, in |z| < 6, its from -5 to 5; with that, statement (1) becomes sufficient.

For (1), lets define the boundarys. Since |x| = { x (in case x>0), -x (in case x<0) }

|z - 2| = z - 2 if z - 2 > 0 ---> z >=2

|z - 2| = -z + 2 if z - 2 < 0 ---> z <=2

assuming z >= 2

|z - 2| > 3
z - 2 > 3
z > 5, so we have here z >= 2 AND z > 5 = z > 5. so, z must be equal to 6 In true, thats no positive value that z can assume.

assuming z <= 2

|z - 2| > 3
-z + 2 > 3
-z > 1
z < -1 , so we have here z <= 2 AND z < -1 = z < -1. so, z can be -2, -3, -4, -5 and -6 . So z can assume a lot for negative numbers here, so (1) is not sufficient . For example, to z = -2:
|z - 2| > 3
|-2 - 2| > 3
|-4| > 3
4 > 3. ( the inequetion its true with z beeing a negative number).

(1) is not sufficient

For (2), we have:
|z| = 2. Since its a equation instead a inequation, we are restrict to z = {2, -2}. Therefore, z can be -2, so (2) its not sufficient .

(2) is not sufficient

Note that even if you assume the 2 afirmations together, z can assume the value z = -2, as I proved on the example before.

So, my answer is Statements 1 and 2 together are not sufficient (E) .

Thats the first time that I read a explanation and didnt gone like "omg, now I understand why I got wrong". But instead Im not understanding why this should be "A", so I dare myself to writte this. Plz, if I said something wrong, correct me asap.
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Bunuel
z is an integer such that |z| < 6. Is z positive?

(1) |z - 2| > 3
(2) |z| = 2
Solution:
Pre Analysis:
  • z is an integer
  • Such that \(|z|<6\) or \(-6<z<6\)
  • So, the possible values of z are -5, -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5
  • We are asked if z is positive integer or not

Statement 1: \(|z - 2| > 3\)
  • From this we can say \(z-2>3\) and \(z-2<-3\)
    \(⇒z>5\) and \(z<-1\)
  • Based on our pre-analysis in step 1, we can infer that z cannot be greater than 5
  • So, the only possible values of z are -2, -3, -4 and -5 and we can be sure that z is not positive
  • Thus, statement 1 alone is sufficient and we can eliminate options B, C and E

Statement 2: \(|z| = 2\)
  • From this, the value of z is either 2 (positive) or -2 (not positive)
  • Thus, statement 2 alone is not sufficient

Hence the right answer is Option A
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