[/quote]
You correctly identified that from (1) we get z < -1 or z > 5. What would be the possible value of z if we also take into the account that |z| < 6 ?[/quote]
I think this one must be E and here its why (
UPDATE: I founded my error, A its the correct answser):
''z is an integer such that |z| < 6. Is z positive?
(1) |z - 2| > 3
(2) |z| = 2 ''
First I wanna say that I understood the question as "can we be sure that z its a positive number?" instead "its possible to z be a positive number?"
The text says: ''z is an integer such that |z| < 6.'', so we know that z can assume the values: {-6, -5, -4....5, 6}
Here's the error, in |z| < 6, its from -5 to 5; with that, statement (1) becomes sufficient.
For (1), lets define the boundarys. Since |x| = { x (in case x>0), -x (in case x<0) }
|z - 2| = z - 2 if z - 2 > 0 ---> z >=2
|z - 2| = -z + 2 if z - 2 < 0 ---> z <=2
assuming z >= 2
|z - 2| > 3
z - 2 > 3
z > 5, so we have here z >= 2 AND z > 5 = z > 5. so, z must be equal to 6
In true, thats no positive value that z can assume.
assuming z <= 2
|z - 2| > 3
-z + 2 > 3
-z > 1
z < -1 , so we have here z <= 2 AND z < -1 = z < -1. so, z can be
-2, -3, -4, -5 and
-6 . So z can assume a lot for negative numbers here, so
(1) is not sufficient . For example, to z = -2:
|z - 2| > 3
|-2 - 2| > 3
|-4| > 3
4 > 3. ( the inequetion its true with z beeing a negative number).
(1) is not sufficient
For (2), we have:
|z| = 2. Since its a equation instead a inequation, we are restrict to z = {2, -2}. Therefore, z can be -2, so
(2) its not sufficient .
(2) is not sufficient
Note that even if you assume the 2 afirmations together, z can assume the value z = -2, as I proved on the example before.
So, my answer is
Statements 1 and 2 together are not sufficient (E) .
Thats the first time that I read a explanation and didnt gone like "omg, now I understand why I got wrong". But instead Im not understanding why this should be "A", so I dare myself to writte this. Plz, if I said something wrong, correct me asap.