ChandlerBong
If p, q, and r are positive integers, is 7p + 9q - r^2 even ?
(1) 6p + q + 5r is an even integer
(2) 3p + 7q + 13r is an odd integer
Question: Is \(7p + 9q - r^2\) even ?
The expression will be even under the following two conditions -
- p, q, and r are even
- Out of the three variables, p, q, and r, two variables are odd and one variable is even
With this pre-analysis done, let's move to the statements
Statement 1(1) 6p + q + 5r is an even integer6p + q + 5r = even
q + 5r = even - 6p
q + 5r = even
This statement holds true when both q and r are odd, and when both q and r are even.
However, we don't know the nature of p. p can be even or odd.
If p, q, and r are even ⇒ Answer to the quesiton Is \(7p + 9q - r^2\) even ? is Yes
If r, q are even and and p is odd ⇒ Answer to the quesiton Is \(7p + 9q - r^2\) even ? is No
As we have two contradicting answers to the question, the statement alone is not sufficient. We can eliminate A and D.
Statement 2(2) 3p + 7q + 13r is an odd integer3p + 7q + 13r = odd
The expression can be odd when
- Two terms are even and one term is odd.
- All the terms are odd
In both cases, the answer to the question Is \(7p + 9q - r^2\) even ? is No
The statement is sufficient.
Option B