Bunuel
On the number line, 0 lies between x and y. Is \(x>y\)?
(1) The distance between x and 0 is 2 times the distance between y and 0
(2) \(x+y>0\)
Given0 lies between x and y
Inference: The question states that 0 lies between x and y, however with the given information we don't know on which side of 0 x and y lie.
With the information given in the premise, we can have two cases.
Case 1: x lies to the right of 0 and y lies to the left of 0
---- y ---------- 0 ---------- x ----
Case 2: x lies to the left of 0 and y lies to the right of 0
---- x ---------- 0 ---------- y ----
Statement 1(1) The distance between x and 0 is 2 times the distance between y and 0Knowing the distance between 0 and either of the points doesn't help us as we are still unaware of the position of x and y.
Both the cases considered in the premise holds valid. Hence, the statement alone is not sufficient.
We can eliminate A and D.
Statement 2(2) \(x+y>0\)Similar to statement 1, we can't predict whether x > y or vice versa.
Ex:
x = 100 , y = -10 ⇒ x > y
x = -10 , y = 100 ⇒ x < y
CombinedFrom statement 1, we can infer that the magnitude of x is greater than the magnitude of y. From statement 2 we know that \(x+y>0\), hence x is positive and y is negative.
Therefore x > y
The statements combined are sufficient.
Option C