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Bunuel
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wminesh
Statement 1 was easy to comprehend.

x>-1 => clearly Statement 1 is Not Sufficient

Tried another way (brute force) of using statement 2:

|x+4| < |x-2| can be written out in 4 different ways:
1. x+4 < x-2 => 4<-2 || Not true
2. x+4 < 2-x => 2x<-2 => x<-1 || Not Suffcient
3. -x-4 < x-2 => -2<2x => -1<x || Not Suffcient
4. -x-4 < 2-x => -4<2 || True, does not give anything about x

Thus, Statement 2 is Not Sufficient.

Answer: E

Would want to hear any comments on the method for using Statement 2.

wminesh

My Two cents -

1) Whenever you're working with signs, you will have to consider the regions in which those signs hold true.

For example

Quote:
2. x+4 < 2-x => 2x<-2 => x<-1 || Not Suffcient

In this case, you have assumed

x + 4 > 0 ⇒ x > -4
x - 2 < 0 ⇒ x < 2

From the working, you arrived at x < -1, not sure why did you indicate the net result as "Not Sufficient" because all it tells us that between -4 and -1 the equation holds true.

Hence, the values of x that satisfy the equation lie between -4 and -1.

So ideally this part is sufficient because all such values are NOT greater than 0.

Similarly -

Quote:
3. -x-4 < x-2 => -2<2x => -1<x || Not Suffcient

In this case, you have assumed

x + 4 < 0 ⇒ x < -4
x + 2 > 0 ⇒ x > -2

The consideration itself is not valid as x cannot be less than -4 and greater than -2 at the same time.

2) You can form regions and evaluate the signs within that region -

Attachment:
Screenshot 2023-03-30 135137.jpg
Screenshot 2023-03-30 135137.jpg [ 57.45 KiB | Viewed 1074 times ]

Hope this clarifies.
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