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What is the median of 12, y, and x? (1) x + y = 24 (2) y = 6 26 Apr 2023, 10:30
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What is the median of 12, y, and x?

(1) x + y = 24
(2) y = 6
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A
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What is the median of 12, y, and x? (1) x + y = 24 (2) y = 6 26 Apr 2023, 11:06
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None of these datasets alone are sufficient, but together they are sufficient. Am not able to see which option corresponds to this answer but there you have it. And median is 12.

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What is the median of 12, y, and x? (1) x + y = 24 (2) y = 6 26 Apr 2023, 22:12
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Option A.

It says, x+y=24.

If x=y, then x=y=12. Median =12 (Set becomes 12, 12, 12).

If x <> y, then either x or y >12 and the other value becomes <12. Median = 12 (Set becomes x, 12, y OR y, 12, x)
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What is the median of 12, y, and x? (1) x + y = 24 (2) y = 6 26 Apr 2023, 22:19
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There is nowhere it states that we should assume x=y though. In the first case of (1), we cannot solve it because we have 1 equation and 2 unknowns, in the case of only (2) we have the same situation. Combining (1) and (2) you get that x = 18, y = 6, and the dataset in ascending order becomes [6, 12, 18]. Median is 12 (the data point in the center). So we must combine (1) and (2), and none of these alone are sufficient but together they are.

va789
Option A.

It says, x+y=24.

If x=y, then x=y=12. Median =12 (Set becomes 12, 12, 12).

If x <> y, then either x or y >12 and the other value becomes <12. Median = 12 (Set becomes x, 12, y OR y, 12, x)
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What is the median of 12, y, and x? (1) x + y = 24 (2) y = 6 27 Apr 2023, 01:36
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Bunuel
What is the median of 12, y, and x?

(1) x + y = 24
(2) y = 6
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Solution:
Pre Analysis:
  • We are asked the median of 12, y, and x

Statement 1: x + y = 24
  • Since \(x+y=24\), we can assume \(x=12-k\) and \(y=12+k\)
    • Where k is any number. Can be 0 as well
  • So, the set will look like either \(12-k,12,12+k\) or \(12+k,12,12-k\) depending on the value of k
  • In both the cases, \(median=12\)
  • Thus, statement 1 alone is sufficient and we can eliminate options B, C and E

Statement 2: y = 6
  • y = 6 will not help us get the value of x and the median of the set
  • Thus, statement 2 alone is not sufficient

Hence the right answer is Option A
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What is the median of 12, y, and x? (1) x + y = 24 (2) y = 6 25 Nov 2023, 06:31
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Dkhapllicator
There is nowhere it states that we should assume x=y though. In the first case of (1), we cannot solve it because we have 1 equation and 2 unknowns, in the case of only (2) we have the same situation. Combining (1) and (2) you get that x = 18, y = 6, and the dataset in ascending order becomes [6, 12, 18]. Median is 12 (the data point in the center). So we must combine (1) and (2), and none of these alone are sufficient but together they are.

va789
Option A.

It says, x+y=24.

If x=y, then x=y=12. Median =12 (Set becomes 12, 12, 12).

If x <> y, then either x or y >12 and the other value becomes <12. Median = 12 (Set becomes x, 12, y OR y, 12, x)

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That's not correct. x + y = 24 implies three cases:

    1. x = y = 12. In this case, the numbers are 12, 12, and 12, giving a median of 12.
    2. x < 12 < y. In this case, the numbers in ascending order are x, 12, and y, giving a median of 12.
    3. y < 12 < x. In this case, the numbers in ascending order are x, 12, and y, giving a median of 12.

So, in any case from (1), we can conclude that the median is 12. Therefore, the correct answer is A, not C.
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What is the median of 12, y, and x? (1) x + y = 24 (2) y = 6 22 Mar 2026, 11:41
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