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Bunuel
Set P consists of 56 integers. Is the product of all the integers in set P negative?

(1) Exactly half of the integers in set P are negative.
(2) Exactly half of the integers in set P are positive.



Given: Set has 56 Integers
Question: is Product of Integers -ive or +ive

Statement 1: Exactly half of the integers in set P are negative.
This means 56/2=28 Integers are -ive, ie. Even Number of Integers are -ive, As Product of Even Number of -ive Integers is Always Positive
Hence, Product of -ive Integers will be Positive, so If any integer is 0 or not, Answer will never be Negative, Statement 1 is Sufficient

Statement 2: Exactly half of the integers in set P are positive.
This means 56/2=28 Integers are +ive
Which Alternatively means Even number of -ive Integer.
If there is any 0 in the mix, Easy Answer-> Product is not Negative
If not, We'll follow the Logic in Statement 1 ; Hence Statement 2 is also Sufficient

Therefore, Answer is D
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