Bunuel
There are two sets of numbers Set A and Set B. Is the average of numbers in Set A greater than that of set B?
(1) The smallest value of set A is larger than the smallest value of set B while the largest value of set A is larger than the largest value of set B
(2) If the smallest and largest values of set A are ignored, the average of the remaining numbers in the set is the same as the previous average of all terms
Statement 1(1) The smallest value of set A is larger than the smallest value of set B while the largest value of set A is larger than the largest value of set BKnowing the relative details of the values will not help us determine whether the average of numbers in Set A greater than that of Set B.
Consider the below two cases:
Case 1A = {0, 10, 20} → Average = 10
B = {-1, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11} → Average = 10
Is the average of numbers in Set A greater than that of set B? → No
Case 2A = {0, 10, 20} → Average = 10
B = {-1, -1} → Average = -1
Is the average of numbers in Set A greater than that of set B? → Yes
As we have two possible cases, the statement alone is not sufficient.
Statement 2(2) If the smallest and largest values of set A are ignored, the average of the remaining numbers in the set is the same as the previous average of all termsWe don't have any information on Set B. Hence, this statement is not sufficient.
CombinedCase 1A = {0, 10, 10, 20} → Average = 10
B = {-1, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11} → Average = 10
Is the average of numbers in Set A greater than that of set B? → No
Case 2A = {0, 10, 10, 20} → Average = 10
B = {-1, -2, -3} → Average = -3
Is the average of numbers in Set A greater than that of set B? → Yes
Hence, the statements combined don't help either.
Option E