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a,b,c,d,e are integers.

Q: Is median> mean? Rephrased Question: Is this an equally spaced set?

1) a<b<c<d<e, tells us that all are not equal, however, it could be in the form of 1,2,3,4,5 which is still an equally spaced set, and has mean = median; therefore, not sufficient.
2) b-a = e-d, tells us nothing other than the difference bw a and b is the same as that bw d and e
1) + 2) set could be in the form of 1,2,3,4,5, in which case mean = median, or 0,2,3,5,7, in which case mean is not equal to median.

Therefore, all insufficient, answer E
Bunuel
If a, b, c, d, and e are integers, is the median of the integers greater than the average (arithmetic mean) of the integers?

(1) a < b < c < d < e
(2) b - a = e - d

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