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Bunuel
­­Two jugs, J and K , contain water. The capacity of jug J is 20 percent greater than that of jug K. How many more gallons of water are in jug J than in jug K ?

(1) When full, jug K holds 5 gallons of water.
(2) Jug J is 50 percent full and jug K is 40 percent full.


­
­


Capacity of jug J is 20 % more than capacity of jug K
J = (6/5)*k----(a)

 (1) capacity of k= 5 gallon
Thus Jug J holds 20% more of this 5 gallon 
i.e 6 gallons (putting k=5 in eq (a))
thus J holds 1 gallon more than K
suff

(2) nothing relevant

Ans A
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IMO A

Please correct me if i am wrong.

Let capacity of Jug K be 10x gallons.
Therefore, capacity of Jug J will be 20% more that Jug K = 12x gallons.
Implies Jug J can hold (12x - 10x ) = 2x more gallons of water than Jug K.

(1) When full, jug K holds 5 gallons of water. --> 5 = 12x, --> We can determine 2x. Sufficient.
(2) Jug J is 50 percent full and jug K is 40 percent full. Insufficient.
­
You are assuming that both the jugs are full with 100% capacity.  Capacity i:e Amount of water Jugs can hold may or may not equal to the actual water present.
I think correct answer will be C. 
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mayankdgmat
IMO (C)

Let Jug K capacity is k, then capacity of jug J is 1.2k

Let Jug J actually filled to be V1 and K to be filled as V2

We need to find V1-V2 = ?

(1) When full, jug K holds 5 gallons of water.

1.2k = 5; we will be able to find k but no idea about V1 or V2. Hence insufficient.

(2) Jug J is 50 percent full and jug K is 40 percent full.

V1 and V2 now we know in terms of k, but we don't know k. Hence insufficient.

(1)+(2) together we know k and hence we can find V1 and V2 with certainty. Hence sufficient together.
­
It says when Jug k holds 5 gallon of water 

which means if we let the capcity of jug k as x then the capacity of J will be 1.2x

(1) It says Jug k holds 5 gallons when full that means the full capacity of Jug J is 5 therfore 1.2x=5 x=6 and diff is 1 


HOW WE DONT KNOW V1 ITS SAYS WHEN FULL IT IS 5 GALLONS
 
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Anugmat740

UnicornAngel
IMO A

Please correct me if i am wrong.

Let capacity of Jug K be 10x gallons.
Therefore, capacity of Jug J will be 20% more that Jug K = 12x gallons.
Implies Jug J can hold (12x - 10x ) = 2x more gallons of water than Jug K.

(1) When full, jug K holds 5 gallons of water. --> 5 = 12x, --> We can determine 2x. Sufficient.
(2) Jug J is 50 percent full and jug K is 40 percent full. Insufficient.
­
You are assuming that both the jugs are full with 100% capacity.  Capacity i:e Amount of water Jugs can hold may or may not equal to the actual water present.
I think correct answer will be C. 
­WHAT THE HELL THE FIRST STATEMENT SAYS WHEN FULL IT CONTAINS 5 GALLONS
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KushagraKirtiman

The expression "when full" is just a modifier, indicating that IF the jug were full, it would contain 5g. That means 5g is its capacity. This doesn't tell us anything at all about the amount of water that is actually in either jug, which is what the question is about. It is these quantities that mayankdgmat labeled as V1 and V2. Make sense?

(By the way, Statement II provides a very big clue here, and this is often a good way to catch our mistakes. If we've assumed the jugs are full, or that volume of water = capacity, then Statement 2 makes it fairly clear that there is a difference!)
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The capacity of jug J is 20% greater than that of jug K, so
J = 1.2K.
We need to find how many more gallons of water are in jug J than in jug K.
[hr]
(1) When full, jug K holds 5 gallons.
→ So J holds 6 gallons (1.2 × 5).
But we don’t know how full either jug is, so we can’t find the difference in water.
Not sufficient.
[hr]
(2) Jug J is 50% full and jug K is 40% full.
→ Water in J = 0.5 × (1.2K) = 0.6K
→ Water in K = 0.4K
Difference = 0.2K
We still don’t know K’s value, so we can’t get a number.
Not sufficient.
[hr]
(1) + (2)
From (1), K = 5.
Difference = 0.2 × 5 = 1 gallon.
Sufficient when combined.
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