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07 Mar 2024, 02:30
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (01:09) correct
15%
(01:25)
wrong
based on 97
sessions
History
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Time
Result
Not Attempted Yet
A drawer contains 12 socks, of which 8 are black and 4 are white. If 3 of the socks are removed, how many of the socks that remain in the drawer are black?
(1) The socks that remain in the drawer have a ratio of 2 black to 1 white.
(2) One of the first two socks removed is black.
(1) The socks that remain in the drawer have a ratio of 2 black to 1 white.
(2) One of the first two socks removed is black.
07 Mar 2024, 03:27
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IMO A
12 socks, 8 black, 4 white
3 are removed
9 socks remain.
Statement 1-
The socks that remain in the drawer have a ratio of 2 black to 1 white.
2 b : 1 w = 6 b : 3 w AND (6+3 = 9 socks total) Sufficient.
Statement 2-
One of the first two socks removed is black.
Which sock is removed in which order is irrelevant to the question.
12 socks, 8 black, 4 white
3 are removed
9 socks remain.
Statement 1-
The socks that remain in the drawer have a ratio of 2 black to 1 white.
2 b : 1 w = 6 b : 3 w AND (6+3 = 9 socks total) Sufficient.
Statement 2-
One of the first two socks removed is black.
Which sock is removed in which order is irrelevant to the question.
07 Mar 2024, 14:50
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Option A
Stateemnt 1:
From 12 socks 3 are removed.
Remaining socks are in the ratio \(\frac{Black}{White}\) = \(\frac{2}{1}\)
Black = 2*White
Black+White = 3*White = 9
White = 3, Black = 6
Sufficient
Statement 2:
One of the first two socks removed is black.
Third sock might or might not be black
Not Sufficient
Only, Statement 1 is sifficient
Hence, Option A
Stateemnt 1:
From 12 socks 3 are removed.
Remaining socks are in the ratio \(\frac{Black}{White}\) = \(\frac{2}{1}\)
Black = 2*White
Black+White = 3*White = 9
White = 3, Black = 6
Sufficient
Statement 2:
One of the first two socks removed is black.
Third sock might or might not be black
Not Sufficient
Only, Statement 1 is sifficient
Hence, Option A
