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03 Apr 2024, 01:30
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
82% (01:35) correct
18%
(02:23)
wrong
based on 111
sessions
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The price per share of stock A increased by 25 percent during the same period of time that the price per share of stock B decreased by 25 percent. The original price per share of stock A was what percent of the original price per share of stock B?
(1) The increased price per share of stock A was equal to the decreased price per share of stock B.
(2) The increase in the price per share of stock A was 3/20 of the original price per share of stock B.
(1) The increased price per share of stock A was equal to the decreased price per share of stock B.
(2) The increase in the price per share of stock A was 3/20 of the original price per share of stock B.
03 Apr 2024, 04:56
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IMO D
Let original price of share A is a and B is b
we need to find a/b in short
(1) 1.25a = 0.75b, so we can find ratio of a/b. Hence suff.
(2) 0.25a = 3/20 b, again we can find a/b. hence suff
Let original price of share A is a and B is b
we need to find a/b in short
(1) 1.25a = 0.75b, so we can find ratio of a/b. Hence suff.
(2) 0.25a = 3/20 b, again we can find a/b. hence suff
03 Apr 2024, 05:21
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Let the original stock price for A = \(a\), which makes the new price \(\frac{5}{4}a\) and the original stock price B = \(b\), with its new stock price being \(\frac{3}{4}b\).
We want \(\frac{a}{b}*100\)
(1) The increased price per share of stock A was equal to the decreased price per share of stock B.
\(\frac{5}{4}a = \frac{3}{4}b \) This will be enough to solve the question as no matter whether one solves for \(a\) or \(b\), plugging either answer back into \(\frac{a}{b}*100\) will cancel out the variables and leave most likely a fraction multiplied by 100.
SUFFICIENT
Solving for a: \(\frac{5}{4}a = \frac{3}{4}b \)
Multiply through by 4: \(5a = 3b \)
\(a = \frac{3}{5}b\) plugging this back into \(\frac{a}{b}*100\):
\(\frac{\frac{3}{5}b}{b}*100\)
\(\frac{3}{5}*100\)
\(60\)%
(2) The increase in the price per share of stock A was 3/20 of the original price per share of stock B.
\(\frac{1}{4}a = \frac{3}{20}b\) as was the case above, solving for either variables and then plugging it back into \(\frac{a}{b}*100\) will result in the canceling out of the variables and yield a percentage.
SUFFICIENT
Solving for a: \(\frac{1}{4}a = \frac{3}{20}b\)
\(a = \frac{3}{5}b\) which is identical to what was solved for in the first statement, and will thus also lead to the same answer of 60%
ANSWER D
We want \(\frac{a}{b}*100\)
(1) The increased price per share of stock A was equal to the decreased price per share of stock B.
\(\frac{5}{4}a = \frac{3}{4}b \) This will be enough to solve the question as no matter whether one solves for \(a\) or \(b\), plugging either answer back into \(\frac{a}{b}*100\) will cancel out the variables and leave most likely a fraction multiplied by 100.
SUFFICIENT
Solving for a: \(\frac{5}{4}a = \frac{3}{4}b \)
Multiply through by 4: \(5a = 3b \)
\(a = \frac{3}{5}b\) plugging this back into \(\frac{a}{b}*100\):
\(\frac{\frac{3}{5}b}{b}*100\)
\(\frac{3}{5}*100\)
\(60\)%
(2) The increase in the price per share of stock A was 3/20 of the original price per share of stock B.
\(\frac{1}{4}a = \frac{3}{20}b\) as was the case above, solving for either variables and then plugging it back into \(\frac{a}{b}*100\) will result in the canceling out of the variables and yield a percentage.
SUFFICIENT
Solving for a: \(\frac{1}{4}a = \frac{3}{20}b\)
\(a = \frac{3}{5}b\) which is identical to what was solved for in the first statement, and will thus also lead to the same answer of 60%
ANSWER D
