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30 May 2024, 12:22
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (01:31) correct
12%
(01:48)
wrong
based on 431
sessions
History
Date
Time
Result
Not Attempted Yet
A box contains exactly 40 bottles, each of which contains only one of three types of soda—orange, lemon, and ginger. What is the probability of randomly selecting a ginger soda, without any replacement in the box, on each of 3 consecutive attempts?
(1) The number of orange sodas is 5 more than the number of ginger sodas.
(2) The number of ginger sodas is 10 more than the number of lemon sodas.
(1) The number of orange sodas is 5 more than the number of ginger sodas.
(2) The number of ginger sodas is 10 more than the number of lemon sodas.
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Archit3110
30 May 2024, 12:29
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Bunuel
given
O+G+L=40
target g/ 40
#1
The number of orange sodas is 5 more than the number of ginger sodas.
L+2g=35
insuffcient
#2
The number of ginger sodas is 10 more than the number of lemon sodas.
G=10+L
O is not known insufficient
from 1 &2
G-10+2G=35
G=15
15/40 ; 3/8
sufficient
option C
14 Jul 2024, 14:41
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Quote:
I get that probability on the first attempt is 15/40. But how it is decided that second is 14/39? There is nowhere in the question that said the first attempt is successful, therefore the probability of second attempt is either 14/39 or 15/39 depending on the outcome of the first attempt.
Could someone please explain?
