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Bunuel
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Hi GMATNinja Bunuel chetan2u Bismuth83

I am a bit confused, what is wrong with my approach here?

R <= $93,300

N < 18000 ?

(1) P > $6

I started trying out different combos of P and N to check on R
Like I got $70,000 by (7, 10000) and $100,000 by (10, 10000)
We get value of R greater than $93,300 as well, hence, (1) is insufficient

Is my approach wrong because I already assumed N<18000?
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Your instinct to test values is good, but the flaw is in assuming N < 18,000 to begin with , which is the very question you're asked to answer.
On DS, we cannot assume what we are supposed to find out.

In Statement (1), we’re told the average price per pretzel > $6

We already know:
R ≤ 70,000 + 0.25R
0.75R ≤ 70,000
So, R ≤ 93,333

Now test P > 6
Try P = 7 ⇒ N = 93,333.33 ÷ 7 ≈ 13,000
P = 8 ⇒ N = 93,333.33 ÷ 8 ≈ 11000

As P increases, N decreases further
So N is always < 18,000

Sufficient

agrasan
Hi GMATNinja Bunuel chetan2u Bismuth83

I am a bit confused, what is wrong with my approach here?

R <= $93,300

N < 18000 ?

(1) P > $6

I started trying out different combos of P and N to check on R
Like I got $70,000 by (7, 10000) and $100,000 by (10, 10000)
We get value of R greater than $93,300 as well, hence, (1) is insufficient

Is my approach wrong because I already assumed N<18000?
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