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Bunuel
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Ayeka
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Bunuel
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­Kevin buys beer in bottles and cans. He pays $1.00 for each can of beer and $1.50 for each bottle of beer. If he buys a total of 15 bottles and cans of beer, how many bottles of beer did he buy?

(1) Kevin spent a total of $18.00 on beer.
(2) Kevin bought 3 more cans of beer than bottles of beer.

The question says how many bottles of beer did Kevin buy.
The question also says he bought a total of 15 bottles and cans of beer.
Assume that no of cans is C and no of bottles is B. The second option says that Kevin bought "3 more cans of beer than bottles of beer". Hence we get C=B+3.
And from the question we already know that C+B=15. Substituting, we get B+B+3=15.
Solving this we get the no of beer cans and bottles. So isn't option B the correct one?

Bunuel, please correct me if I'm wrong.
Thanks

Please check the solution just above your post. The first statement is also sufficient, so the answer is D, not B.
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