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Bunuel
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Given:
There is a list of 16 possible class sizes:
58,60,62,64,66,68,70,72,74,76,78,80,82,84,86,88.
We are to select 10 unique numbers from this list.
We need to find the standard deviation of these 10 selected numbers.
Statement (1)
The median number of students is equal to the mean number of students in the 10 classes.
This suggests that the distribution of class sizes selected has symmetry, meaning the 10 selected values might be symmetrically distributed around their mean. However, we do not know exactly which values are chosen, nor do we have enough information to determine if this symmetry will result in a specific standard deviation.

Statement (1) alone is insufficient.

Statement (2)
The number of students in any class is more than 63.
The average number of students in the 10 classes is the same as the average of the entire list.
First, calculate the average of the entire list:

Sum of all 16 values=58+60+62+...+88=1168
Average=1168/16=73

So, the average number of students in the 10 classes is also 73.

Since each class size is more than 63, the selected numbers must be chosen from
64,66,68,70,72,74,76,78,80,82,84,86,88.

To get an average of 73 with 10 values, the selected numbers need to be symmetrically centered around 73. A possible selection meeting these criteria is
64,66,68,70,72,74,76,78,80,82.

The standard deviation of this set can be calculated, and since these are the only numbers that satisfy both criteria, Statement (2) alone is sufficient.

Conclusion:
The answer is (B): Statement (2) alone is sufficient.
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For option A my reasoning was:
Whatever 10 numbers are chosen, they'll be in series with a difference of 2.
Eg series 1 :(64,66,68,70,72,74,76,78,80,82)
mean= 73 and diff for obs from mean is (64-73)^2+ (66-73)^2 and so on.. diff will be symmetrical both sides of mean i.e 2[9^2+7^2+ 5^2+3^2+1^2}

Now considering another series:( 70,72,74,76,78,80,82,84,86,88) mean = 79
diff for obs from mean is ((70-79)^2 + (72-790^2 and so on diff will be symmetrical both sides of mean i.e 2[9^2+7^2+ 5^2+3^2+1^2}


hence, we can actually find STd devation

Please let me know what am I missing KarishmaB Bunuel EgmatQuantExpert
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Bunuel
58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88

The number of students in each of 10 different classes is a different number from the above list. What is the standard deviation of the number of students in the 10 classes?

(1) The median number of students is equal to the mean number of students in the 10 classes.

(2) The number of students in any class is more than 63 and the average number of students in the 10 classes is same as the average of the above list.


­

Sunpreet19 - Statement 1 alone is not sufficient.

(1) The median number of students is equal to the mean number of students in the 10 classes.

The numbers can be chosen as:
58, 60, 62, 64, 66, 68, 70, 72, 74, 76 (an Arithmetic Progression)
or as
58, 60, 62, 64, 66, 72, 74, 76, 78, 80 (not an AP) Here also mean = median = 69

SD in the two cases is different. Many such different cases are possible.

Hence statement 1 alone is not sufficient.

Keep in mind: For all APs, Mean = median
But mean = median does not imply that it is an AP
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