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A box of chocolates has 15 rows with 10 spaces for chocolates in each row, how many chocolates are in the box?
There are total 15*10=150 spaces for the chocolate.

(1) There is an average (arithmetic mean) of 6 empty spaces in the first 8 rows.
6*8=48 empty spaces in first 8 rows...We don’t know about last 7 rows.
Insufficient

(2) There is an average (arithmetic mean) of 9 empty spaces in the last 9 rows.
9*9=81 empty spaces in last 9 rows...we don’t know about first 6 rows.
Insufficient

(1)&(2)
48 empty spaces in first 8 rows and 81 empty spaces in last 9 rows. There is an overlap. So, we can’t find the exact number.
Insufficient

E
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Why is C wrong? If we take first 8 rows and 9 rows from the bottom we will get the total number of empty spaces for all 15? where am i going wrong
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MegB07
A box of chocolates has 15 rows with 10 spaces for chocolates in each row, how many chocolates are in the box?

(1) There is an average (arithmetic mean) of 6 empty spaces in the first 8 rows.
(2) There is an average (arithmetic mean) of 9 empty spaces in the last 9 rows.

Why is C wrong? If we take first 8 rows and 9 rows from the bottom we will get the total number of empty spaces for all 15? where am i going wrong

This is basically an overlapping sets problem in disguise.

From statement (1), the first 8 rows have 6 empty spaces on average which means 48 empty spaces and 32 chocolates.

From statement (2), the last 9 rows have 9 empty spaces on average which means 81 empty spaces and 9 chocolates.

Rows 7 and 8 are included in both groups. Because we do not know how many chocolates are in these two overlap rows, we cannot resolve the double count.

If all 9 chocolates from the last 9 rows are in rows 7 and 8, the total could be 32. If rows 7 and 8 are completely empty and the 9 chocolates are in rows 9 through 15, the total could be 41. So the total number of chocolates can be as low as 32 or as high as 41 or something in between.

Answer: E.
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