In a packet of M&M chocolates, there are only two colored M&M chocolates i.e. Green and Red. If two chocolates are picked randomly, then what is the probability of picking two red M&M chocolates?
(1) The probability of the first M&M chocolate being Green is 1/3.
(2) There are 48 red M&M chocolates in the packet.
We need to find out the probability of picking 2 red M&M chocolates. Let's look at each statement individually and then at both of them together (if required):
Statement 1: The probability of the first M&M chocolate being Green is 1/3.
Since there are only red and green chocolates, P(Red) = 2/3
Thus, ratio of red chocolates to the total number of chocolates = 2/3
However, we do not know the total number of chocolates, thus, there can be different probabilities associated.
Hence, Statement 1 is insufficient alone.
Now, let's take a look at Statement 2 closely:
Statement 2: There are 48 red M&M chocolates in the packet.
Even though we are given the number of red chocolates in the packet, we do not know the total number of chocolates in the packet.
Hence, Statement 2 is insufficient alone as well.
Now, let's take a look at the combination of both statements - Statement 1 and Statement 2:
Red = 2/3 of total
Red = 48
Now, total is fixed: Total = 3/2 * 48 = 72=> Probability is fixed.
P(Two Reds) = 48/72 * 47/71
Hence, the correct answer is
Option C - BOTH statements (1) and (2) TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
Hope this helps!