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Amity007
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I could not understand how the second line follows from the first line
(1+p/100)(1+q/100)(1-r/100) >1
(100+p)(100+q)(100-r)>100

tryorcry
Let the price of stock in 2018 be 100.
then price of stock in 2020 = 100(1+p/100)(1+q/100)
price after r% decrease = 100(1+p/100)(1+q/100)(1-r/100)------A
As per the question , we have to find if A >100 or not
So, assuming A>100
(1+p/100)(1+q/100)(1-r/100) >1
(100+p)(100+q)(100-r)>100

as per statement 1 which is p + q > r
let p=100, q=200 , r = 150
then value is in negative which is less than 100.
if we put p=1, q=100 and r=99 then value is greater than 100. So Statement 1 is NOT SUFFICIENT

Statament 2 , q – p > r
which is , q>p+r
p=1, r=1, q=5
then its greater than 100, but if
r=150, p=1, q=1000
whole value is in negative , hence statement 2 also INSUFFICIENT

Hence , option E

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kartickdey
I could not understand how the second line follows from the first line
(1+p/100)(1+q/100)(1-r/100) >1
(100+p)(100+q)(100-r)>100


Hi Katrickdey,
I just skipped a middle line where I am taking the LCM as 100 and sending is to RHS

(1+p/100)(1+q/100)(1-r/100) >1
((100+p)(100+q)(100-r))/100 > 1
(100+p)(100+q)(100-r)>100
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Anyway I got your logic. It was useful explanation.
What I wanted to mean is that I think on the right hand side instead of 100 it will be 1000000 as all the terms are in multiplication order. There is no scope to take 100 common out of the terms. It will be in order of 10^6
tryorcry


Hi Katrickdey,
I just skipped a middle line where I am taking the LCM as 100 and sending is to RHS

(1+p/100)(1+q/100)(1-r/100) >1
((100+p)(100+q)(100-r))/100 > 1
(100+p)(100+q)(100-r)>100
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kartickdey
Anyway I got your logic. It was useful explanation.
What I wanted to mean is that I think on the right hand side instead of 100 it will be 1000000 as all the terms are in multiplication order. There is no scope to take 100 common out of the terms. It will be in order of 10^6



Yes, that's a very good catch. I missed 4 zeroes. Thanks , however the remaining processes will be same only the value taken for percentage will change to show both are insufficient
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