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Updated on: 04 Feb 2026, 10:11
Originally posted by ExpertsGlobal5 on 03 Feb 2026, 23:33.
Last edited by Bunuel on 04 Feb 2026, 10:11, edited 1 time in total.
Last edited by Bunuel on 04 Feb 2026, 10:11, edited 1 time in total.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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58% (01:37) correct
43%
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What is the percentage of alcohol in solution X?
(1) If 50 liters alcohol is added, X will contain 60% alcohol.
(2) If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
(1) If 50 liters alcohol is added, X will contain 60% alcohol.
(2) If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
04 Feb 2026, 00:03
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Assume solution X has "a" L of alcohol and total solution is V L. Need to find (a/V)
1. Add 50L alcohol: (50+a)/(V+50) = 60% -> it will give a linear eqn with 2 variables a and V. Cant solve for a.
2. Add water same as total volume of X: a/(V+V) = 20% -> we can find (a/V)
Thus statement 2 alone is sufficient, not 1.
B.
1. Add 50L alcohol: (50+a)/(V+50) = 60% -> it will give a linear eqn with 2 variables a and V. Cant solve for a.
2. Add water same as total volume of X: a/(V+V) = 20% -> we can find (a/V)
Thus statement 2 alone is sufficient, not 1.
B.
04 Feb 2026, 00:19
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What is the percentage of alcohol in solution X?
(1) If 50 liters alcohol is added, X will contain 60% alcohol.
(2) If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
Let the volume of the original solution be 'V' liters, and the alcohol content in it be 'A' liters.
Thus, percentage of alcohol in solution X = (A/V)*100
Let's look at each statement individually and then at both of them together (if required):
Statement 1: If 50 liters alcohol is added, X will contain 60% alcohol.
Volume of alcohol now = A+50
Volume of solution now = V+50
Thus, alcohol percentage in X = (A+50)/(V+50) = 60/100 = 0.6
However, since we have 2 variables and only 1 equation, we cannot uniquely find the answer. Hence, Statement 1 is insufficient alone.
Now, let's take a look at Statement 2 closely:
Statement 2: If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
Volume of water added = V
Volume of alcohol = A
Volume of solution now = V+V = 2V
Thus, alochol percentage of solution = A/2V = 0.2 => A/V = 0.4 (or 40%)
Therefore, the percentage of alcohol in solution X = 40% (uniquely determined using Statement 2 alone)
Hence, the correct answer is Option B - Statement (2) alone is sufficient, but statement (1) alone is not sufficient.
Hope this helps!
(1) If 50 liters alcohol is added, X will contain 60% alcohol.
(2) If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
Let the volume of the original solution be 'V' liters, and the alcohol content in it be 'A' liters.
Thus, percentage of alcohol in solution X = (A/V)*100
Let's look at each statement individually and then at both of them together (if required):
Statement 1: If 50 liters alcohol is added, X will contain 60% alcohol.
Volume of alcohol now = A+50
Volume of solution now = V+50
Thus, alcohol percentage in X = (A+50)/(V+50) = 60/100 = 0.6
However, since we have 2 variables and only 1 equation, we cannot uniquely find the answer. Hence, Statement 1 is insufficient alone.
Now, let's take a look at Statement 2 closely:
Statement 2: If the volume of water, equivalent to that of the total solution, is added, X will contain 20% alcohol.
Volume of water added = V
Volume of alcohol = A
Volume of solution now = V+V = 2V
Thus, alochol percentage of solution = A/2V = 0.2 => A/V = 0.4 (or 40%)
Therefore, the percentage of alcohol in solution X = 40% (uniquely determined using Statement 2 alone)
Hence, the correct answer is Option B - Statement (2) alone is sufficient, but statement (1) alone is not sufficient.
Hope this helps!
