Last visit was: 22 Apr 2026, 23:16 It is currently 22 Apr 2026, 23:16
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
ExpertsGlobal5
User avatar
Experts' Global Representative
Joined: 10 Jul 2017
Last visit: 22 Apr 2026
Posts: 6,216
Own Kudos:
6,175
 [2]
Given Kudos: 44
Location: India
GMAT Date: 11-01-2019
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 6,216
Kudos: 6,175
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
shivani1351
Joined: 23 Apr 2021
Last visit: 20 Apr 2026
Posts: 152
Own Kudos:
78
 [5]
Given Kudos: 5
Posts: 152
Kudos: 78
 [5]
5
Kudos
Add Kudos
Bookmarks
Bookmark this Post
General Discussion
User avatar
Xdsa
Joined: 07 Jul 2025
Last visit: 22 Apr 2026
Posts: 57
Own Kudos:
45
 [1]
Given Kudos: 1
Posts: 57
Kudos: 45
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Dereno
Joined: 22 May 2020
Last visit: 22 Apr 2026
Posts: 1,398
Own Kudos:
1,373
 [1]
Given Kudos: 425
Products:
Posts: 1,398
Kudos: 1,373
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ExpertsGlobal5
Lee, Dimitra, and Jan, each had to pay a fine for accidental property damage. If the total amount paid by the 3 was $900, what was the median amount?

(1) Jan was fined $300.
(2) Lee and Dimitra were fined a total of $600.


Experts' Global
This Daily Butler Question was provided by Experts' Global
Sponsored


­
Lee, Dmitria and Jan were asked to pay a fine totalling $900.

We need to find : Median value

Statement 1:

Jan was fined $300.

if Jan was fined $300. Then the amount paid by Lee and Dmitria equals 900-300 = $600.

The split up between Lee and Dmitiria can be of many values. (1,599);(2,598),.........(598,2);(599,1).

With any value across the spectrum. Jan occupies the middle value.

(1,300,599)
.
....
(599,300,1).

Hence, Sufficient.

Statement 2:

Lee and Dimitra were fined a total of $600.

If Lee and Dimitra were fined a total of $600, then Jan = $300.

This is same as the statement 1.

Hence, Sufficient

Option D
User avatar
nemoexplicabo
Joined: 02 Feb 2026
Last visit: 22 Apr 2026
Posts: 17
Own Kudos:
Given Kudos: 18
Posts: 17
Kudos: 8
Kudos
Add Kudos
Bookmarks
Bookmark this Post
This is a great median problem that tests whether you can recognize when you have enough information about a set of numbers to determine their median — a classic Data Sufficiency concept!

The question asks: If Lee, Dimitra, and Jan each paid a fine and the total was $900, what was the median fine?

Since we have 3 values, the median will be the middle value when the three fines are arranged in order.

Statement (1): Jan was fined $300

From this, we know:
- Jan = $300
- Lee + Dimitra = $900 - $300 = $600

Now here's the key insight: No matter how we split $600 between Lee and Dimitra, when we arrange all three values in order, $300 will ALWAYS be the median.

Let me show you why with a few examples:
- If Lee = $200 and Dimitra = $400: Ordered = {$200, $300, $400} → Median = $300
- If Lee = $100 and Dimitra = $500: Ordered = {$100, $300, $500} → Median = $300
- If Lee = $300 and Dimitra = $300: Ordered = {$300, $300, $300} → Median = $300
- If Lee = $450 and Dimitra = $150: Ordered = {$150, $300, $450} → Median = $300

Since $300 is exactly one-third of the total ($900), and the other two values must sum to twice that amount ($600), $300 will always fall in the middle position.

Statement (1) is SUFFICIENT.

Statement (2): Lee and Dimitra were fined a total of $600

This tells us:
- Lee + Dimitra = $600
- Jan = $900 - $600 = $300

Wait a minute — this gives us exactly the same information as Statement 1! We know Jan = $300, and the analysis is identical. The median must be $300.

Statement (2) is SUFFICIENT.

Answer: D

Common traps to avoid:

A common mistake is thinking that Statement 1 is insufficient because "we don't know how $600 is split between Lee and Dimitra." But in Data Sufficiency, we don't need to find all individual values — we only need to determine if we can find the median. The beautiful thing about this problem is that the median doesn't depend on how the remaining money is distributed. Another trap is not recognizing that Statements 1 and 2 are actually giving the same information in different forms — if you know Jan's fine, you know the sum of the other two, and vice versa.

Key takeaway: For median problems with an odd number of values, you don't always need to know every individual value. If you know enough about the structure of the data set, you can sometimes determine the median even with some unknowns. In this case, knowing one value that equals exactly one-third of the total locks in the median position. This is a powerful concept that applies whenever you have constraints that force certain values into fixed positions in the ordered list!
User avatar
ExpertsGlobal5
User avatar
Experts' Global Representative
Joined: 10 Jul 2017
Last visit: 22 Apr 2026
Posts: 6,216
Own Kudos:
Given Kudos: 44
Location: India
GMAT Date: 11-01-2019
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 6,216
Kudos: 6,175
Kudos
Add Kudos
Bookmarks
Bookmark this Post
ExpertsGlobal5
Lee, Dimitra, and Jan, each had to pay a fine for accidental property damage. If the total amount paid by the 3 was $900, what was the median amount?

(1) Jan was fined $300.
(2) Lee and Dimitra were fined a total of $600.

Explanation:

The total amount paid by Lee, Dimitra, and Jan = $900. Hence, the average amount paid by them was $300.
We need to find whether the median amount paid by Lee, Dimitra, and Jan can be determined.

Statement (1)

Jan was fined $300.

Since the average amount paid was $300, maintaining this average requires that both of the other two values are either equal to $300, or one of them is greater than $300 while the other is less than $300. In either case, the median will be $300.

It is possible to determine the median amount paid by Lee, Dimitra, and Jan. Hence, Statement (1) is sufficient.

Statement (2)

Since the total fine paid = 3 x 300 = $900, and Lee and Dimitra paid a total of $600, it follows that Jan must have paid 900 – 600 = $300.

After that, similar reasoning as above can be used to show that it is possible to determine the median amount paid by Lee, Dimitra, and Jan. Hence, Statement (2) is sufficient.

D is the correct answer choice.
Moderators:
Math Expert
109763 posts
498 posts
212 posts