This is a weighted average problem disguised as Data Sufficiency. The key concept being tested is whether you can connect percentages to actual quantities.
Step 1: Set up what we know
Let T = total number of sacks
60% of sacks meet the listed weight (0.6T sacks)
40% are under weight (0.4T sacks)
We need to find T.
Step 2: Analyze Statement (1)
Statement (1): The listed weight is 150 pounds, and the total weight of sacks that meet it is 22,500 pounds.
If each of the 0.6T sacks weighs exactly 150 pounds, then:
0.6T x 150 = 22,500
90T = 22,500
T = 250
This gives us a definite answer.
Sufficient on its own.
Step 3: Analyze Statement (2)
Statement (2): The total number of sacks that don't meet the listed weight is 100.
If 40% of sacks = 100, then:
0.4T = 100
T = 250
This also gives us a definite answer.
Sufficient on its own.
Step 4: Determine the answer
Since each statement alone is sufficient, the answer is D (each alone is sufficient).
Common trap: Many students think Statement (1) is insufficient because it doesn't tell us about the underweight sacks. But we don't need that information — we know 60% meet the weight, and Statement (1) tells us exactly how many that is through the total weight. This is a classic DS trap where students assume they need more information than they actually do. Always ask yourself: "Can I find what's being asked with JUST this statement?" before dismissing it.
Takeaway: In Data Sufficiency with percentages, if you know the percentage AND the actual count (or total value) for any single part, you can always find the whole. Don't fall for the trap of thinking you need information about all the pieces.