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Company M has two divisions- X and Y. Both the divisions have exactly 15 Feb 2026, 20:00
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65% (hard)

Question Stats:

56% (01:47) correct 44% (01:40) wrong based on 121 sessions

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Company M has two divisions- X and Y. Both the divisions have exactly two types of employees - operators and executives. Is the ratio of number of operators to executives greater for division X than for division Y?

(1) The ratio of operators to executives for the division X is less than that for the company M.
(2) The ratio of operators to executives for the division Y is greater than that for the company M.



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D
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Company M has two divisions- X and Y. Both the divisions have exactly 15 Feb 2026, 23:06
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ExpertsGlobal5
Company M has two divisions- X and Y. Both the divisions have exactly two types of employees - operators and executives. Is the ratio of number of operators to executives greater for division X than for division Y?

(1) The ratio of operators to executives for the division X is less than that for the company M.
(2) The ratio of operators to executives for the division Y is greater than that for the company M.



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Comapny M has two divisions X and Y. The division have two types of employees - Operator and Executives.

We need to find: Is the ratio of number of operators to executives greater for division X than for division Y?

Let a and c be the number of Operators for X and Y respectively.

Let b and d be the number of Executives for X and Y respectively.

Is (a/b) > (c/d)?

Statement 1:

The ratio of operators to executives for the division X is less than that for the company M.

(a/b) < (a+c)/ (b+d)

Hence, if one of the group is less than the average , then the other group must be more than the average to compensate for the difference.

Thus, sufficient

Statement 2:

The ratio of operators to executives for the division Y is greater than that for the company M.

(c/d) > (a+c)/ (b+d)

Hence, if one of the group is less than the average , then the other group must be more than the average to compensate for the difference.

Thus, sufficient

Option D
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Company M has two divisions- X and Y. Both the divisions have exactly 17 Feb 2026, 08:00
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Q : Is X > Y ?

1.) X < Company

if X is below average , Y must be above it
So X < Y -> No
So (1) is sufficient

2.) Y > Company
if Y is above average, X must be below it.
So X < Y -> No
So (2) is sufficient

Answer D
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Company M has two divisions- X and Y. Both the divisions have exactly 22 Feb 2026, 03:00
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ExpertsGlobal5
Company M has two divisions- X and Y. Both the divisions have exactly two types of employees - operators and executives. Is the ratio of number of operators to executives greater for division X than for division Y?

(1) The ratio of operators to executives for the division X is less than that for the company M.
(2) The ratio of operators to executives for the division Y is greater than that for the company M.
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Explanation:

Statement (1)

If the ratio (of operators to executives) for the division X is less than the ratio for the two sections combined, it means that the ratio for section Y must be greater.
Hence, we can deduce that “No, the ratio of number of operators to executives is NOT greater for division X than for division Y”.
Sufficient.

Statement (2)

If the ratio (of operators to executives) for the division Y is greater than the ratio for the two sections combined, it means that the ratio for section X must be lesser.
Hence, we can deduce that “No, the ratio of number of operators to executives is NOT greater for division X than for division Y”.
Sufficient.

Each statement alone is sufficient.

D is the correct answer choice.
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Company M has two divisions- X and Y. Both the divisions have exactly 22 Feb 2026, 14:27
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Answer: D — both statements are individually sufficient. The core concept being tested here is the Weighted Average Seesaw, one of the most important ideas in GMAT Data Sufficiency.

The logic works like this: when you combine two groups, the combined ratio (the "company average") is always between the two individual ratios. It's a weighted average. If one group is below the combined average, the other group must be above it to balance things out. There's no way both can be below (or both above) the overall average at the same time.

Statement (1): X's ratio < Company M's ratio
This tells us X is below the combined average. By the seesaw logic, Y must be above it. So X < Company M < Y, which directly answers the question — No, X's ratio is NOT greater than Y's. Sufficient.

Statement (2): Y's ratio > Company M's ratio
This tells us Y is above the combined average. By the same logic, X must be below it. So X < Company M < Y — again the answer is No. Sufficient.

Each statement alone is sufficient → Answer D.

The common trap here: students try to test with actual numbers and run into algebra, then get confused about whether it's always true or just sometimes true. If you recognize the weighted average constraint upfront, you never need to plug numbers — the conclusion follows immediately from the structure.

Takeaway: Whenever a DS question gives you information about a subgroup's ratio relative to the combined group's ratio, the Weighted Average Seesaw tells you the other subgroup's position immediately.
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