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Great explanation above! One thing worth flagging for anyone who wants to internalize the logic quickly: this is a classic Divisibility + Number Properties DS pattern that the GMAT Focus Edition uses frequently in Word Problems.

The core of this question is recognizing that two divisibility constraints on x give you a periodic set of solutions — not just one or two random values. Once you spot that x must be divisible by 10 and x+10 must be divisible by 12, you're really solving for x = 50 (mod 60), which gives the sequence 50, 110, 170, 230... The LCM of 10 and 12 (= 60) controls the spacing.

The trap in Data Sufficiency here is thinking "two inequalities should pin down one value" — but they don't, because the feasible set {50, 110, 170...} has multiple values between 100 and 180, specifically 110 and 170. Always verify DS sufficiency by checking whether the constraints together produce a unique value, not just a reduced set.

Answer: E — neither statement alone nor together is sufficient.
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The hotel manager divided the freshly vacated rooms for cleaning, equally among 10 housekeepers with none left over. 10 rooms were then vacated ahead of time and in response, the manager redivided all freshly vacated rooms equally among 12 housekeepers, with no rooms left over. How many freshly vacated rooms were there before 10 rooms were vacated ahead of time?

(1) Before the 10 rooms were vacated ahead of time, there were more than 100 freshly vacated rooms.
(2) Before the 10 rooms were vacated ahead of time, there were fewer than 180 freshly vacated rooms.
Explanation:

Let the initial number of vacated rooms be X.
Since the manager divided the rooms equally among 10 housekeepers with none left over: X is a multiple of 10.
The final number of vacated rooms after 10 more rooms were vacated = X + 10
Since the manager divided (X + 10) rooms equally among 12 housekeepers with none left over: (X + 10) is a multiple of 12.
We need to find whether the value of X can be determined.

Statement (1)

Since X > 100 and X is a multiple of 10, possible values of X are 110, 120, 130, 140, 150, 160, and so on.
However, since (X + 10) also needs to be a multiple of 12, the values of X that satisfy all the conditions are 110, 170, 230, and so on.

It is NOT possible to determine with certainty the value of X. Hence, Statement (1) is insufficient.

Statement (2)

Since X < 180 and X is a multiple of 10, possible values of X are 170, 160, 150, 140, 130, 120, 110, and so on.
However, since (X + 10) also needs to be a multiple of 12, the values of X that satisfy all the conditions are 170, 110, and 50.

It is NOT possible to determine with certainty the value of X. Hence, Statement (2) is insufficient.

As Statement (1) alone as well as Statement (2) alone is insufficient to answer the question, we need to now combine the two statements.

Statement (1) and Statement (2) combined

The two statements combined give us X = 110 and X = 170 as two solutions that satisfy all the conditions.

It is NOT possible to determine with certainty the value of X. Hence, Statement (1) and Statement (2) combined are insufficient.

E is the correct answer choice.
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Let total number of rooms before vacating be 't', let initial number of rooms assigned to each house keeper be a and number of rooms assigned to each housekeeper after 10 rooms were vacated be b
So, t=10a and t-10=12 b
or, 5a-5= 6b

Option 1:
T>100
Or, 10 a > 100
Or, a> 10
Not sufficient

Option 2:
T <180
Or, 10a <180
Or, a <18

Option 1+2:
10< a <18
So, a= 11,12,13,14,15,16,17
Now, 5a -5=6 b
Or, b= (5a-5)/6
Only possible value of a that makes (5a -5) divisible by 6 is 13
So, t=10a or t=130
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