Let's call the original number of freshly vacated rooms
x.
From the question stem, we get two key constraints:Constraint 1: x is divisible by
10 (rooms divided equally among 10 housekeepers, none left over)
Constraint 2: x + 10 is divisible by
12 (after 10 more rooms vacated, divided equally among 12 housekeepers)
Finding the possible values of x:Numbers divisible by 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180...
Now check which of these, when we add 10, give a number divisible by 12:
• x =
50 → 50 + 10 = 60 ✓ (divisible by 12)
• x =
110 → 110 + 10 = 120 ✓ (divisible by 12)
• x =
170 → 170 + 10 = 180 ✓ (divisible by 12)
• x =
230 → 230 + 10 = 240 ✓ (divisible by 12)
The pattern: x = 50, 110, 170, 230, 290... (increases by 60 each time - LCM of 10 and 12)Statement 1: Before the 10 rooms were vacated, there were more than 100 rooms.
So x > 100. Possible values:
110, 170, 230, 290...Multiple values possible →
Not SufficientStatement 2: Before the 10 rooms were vacated, there were fewer than 180 rooms.
So x < 180. Possible values:
50, 110, 170Multiple values possible →
Not SufficientCombining Both Statements:100 < x < 180
Possible values:
110 and
170Even with both constraints combined, we still have TWO possible values!Case 1: x = 110 rooms originally, then 120 rooms after (120 ÷ 12 = 10 rooms per housekeeper) ✓
Case 2: x = 170 rooms originally, then 180 rooms after (180 ÷ 12 = 15 rooms per housekeeper) ✓
Both cases satisfy ALL conditions, but give different answers.
Answer: E