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24 Feb 2026, 22:18
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (01:34) correct
27%
(01:52)
wrong
based on 70
sessions
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The percentage of alcohol in bottle A is 30 and the percentage of alcohol in bottle B is 70. What is the ratio of volumes of the liquids in bottles A and B?
(1) When the liquids in the two bottles are mixed in a bigger container, the percentage of alcohol in the resultant liquid is 40.
(2) If one-third of the volume of the liquid from bottle A is mixed with half of the volume of the liquid from bottle B, the percentage of alcohol in the resultant solution is 43.33%.
(1) When the liquids in the two bottles are mixed in a bigger container, the percentage of alcohol in the resultant liquid is 40.
(2) If one-third of the volume of the liquid from bottle A is mixed with half of the volume of the liquid from bottle B, the percentage of alcohol in the resultant solution is 43.33%.
25 Feb 2026, 01:32
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If you know allegations, this question will be a breeze.
Two mixtures with their respective concentration of somethings(here alcohol) and then followed by their resultant mixture's concentration(here resultant concentration of alcohol after mixing) gives us directly the ratio of the mixtures.
Someone who has solved many questions using "allegation" approach will have this naturally.
Statement 1: Clearly Sufficient
Statement 2: Here the thing is, suppose I have a solution which consist of 70% alcohol and 30% water and if I take out 100ml/1000ml/1ml or whatsoever, then also the "taken out" sample will have 70% alcohol and 30% water.
So, one-third of the volume of the liquid from bottle A is mixed with half of the volume of the liquid from bottle B, still implies that alcohol in one-third of the volume of A is 30 and the half of the volume of the liquid from bottle B is also having alcohol as 70%
Again you can get the respective volumes and then convert 1/3 to full and similarly half to full for the second.
Statement 2 is also Sufficient
Answer is option(D)
Two mixtures with their respective concentration of somethings(here alcohol) and then followed by their resultant mixture's concentration(here resultant concentration of alcohol after mixing) gives us directly the ratio of the mixtures.
Someone who has solved many questions using "allegation" approach will have this naturally.
Statement 1: Clearly Sufficient
Statement 2: Here the thing is, suppose I have a solution which consist of 70% alcohol and 30% water and if I take out 100ml/1000ml/1ml or whatsoever, then also the "taken out" sample will have 70% alcohol and 30% water.
So, one-third of the volume of the liquid from bottle A is mixed with half of the volume of the liquid from bottle B, still implies that alcohol in one-third of the volume of A is 30 and the half of the volume of the liquid from bottle B is also having alcohol as 70%
Again you can get the respective volumes and then convert 1/3 to full and similarly half to full for the second.
Statement 2 is also Sufficient
Answer is option(D)
25 Feb 2026, 03:24
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Given the volume of Alcohol in bottle A = 30% or 0.3A
Also, the volume of Alcohol in bottle B = 70% or 0.7B
We are asked the A:B=?
(1) When the liquids in the two bottles are mixed in a bigger container, the percentage of alcohol in the resultant liquid is 40.
Since the resultant solution is talking about the percentage of alcohol, let's solve for alcohol to the whole solution.
So, (0.3A+0.7B)/(A+B) = 40/100
From here onwards, we don't need to solve to know that it is sufficient.
(FYI- Upon solving, we'd get A:B=3:1)
(2) If one-third of the volume of the liquid from bottle A is mixed with half of the volume of the liquid from bottle B, the percentage of alcohol in the resultant solution is 43.33%.
Again, since the resultant solution is talking about alcohol, we can set up an equation for the alcohol as per the required.
(1/3)x(0.3A) and (1/2)x(0.7B) to get the alcohol concentration total.
Accordingly, we can solve as we did in the option A. Hence, sufficient.
Option D
Also, the volume of Alcohol in bottle B = 70% or 0.7B
We are asked the A:B=?
(1) When the liquids in the two bottles are mixed in a bigger container, the percentage of alcohol in the resultant liquid is 40.
Since the resultant solution is talking about the percentage of alcohol, let's solve for alcohol to the whole solution.
So, (0.3A+0.7B)/(A+B) = 40/100
From here onwards, we don't need to solve to know that it is sufficient.
(FYI- Upon solving, we'd get A:B=3:1)
(2) If one-third of the volume of the liquid from bottle A is mixed with half of the volume of the liquid from bottle B, the percentage of alcohol in the resultant solution is 43.33%.
Again, since the resultant solution is talking about alcohol, we can set up an equation for the alcohol as per the required.
(1/3)x(0.3A) and (1/2)x(0.7B) to get the alcohol concentration total.
Accordingly, we can solve as we did in the option A. Hence, sufficient.
Option D
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