Great Data Sufficiency question — it tests a subtle but important concept in Statistics and Sets Problems: the difference between what a sum tells you versus what a median tells you about the distribution of a dataset.
Key concept being tested: Properties of the median in an even-sized set, and how the median pins down a minimum count in a way that the sum cannot.
Step 1 — Set up the problem.
We have 12 numbers. Each is positive (profit), negative (loss), or zero (break-even). The question asks: are there more months with a positive number than months with a negative number?
Step 2 — Evaluate Statement (1): The sum of the 12 numbers is less than 0.
The sum being negative does NOT tell us how many months were profitable. One month with a large loss (say, -1000) can drag the sum below zero even if 11 months were profitable. Alternatively, all 12 months could be loss months. Not sufficient.
Common trap: Students instinctively think "sum negative → more losses." But one huge negative number can overpower 11 small positive ones.
Step 3 — Evaluate Statement (2): The median of the 12 numbers is less than 0.
With 12 numbers, the median is the average of the 6th and 7th values when sorted in ascending order. For the median to be less than 0, both the 6th and 7th values (in sorted order) must be negative — otherwise their average could not be negative. So positions 6, 7, 8, 9, 10, 11, 12 are all ≤ 0, meaning at least 7 months recorded a loss or break-even. At most 5 months could be profitable. So the number of profit months (at most 5) cannot exceed the number of loss months (at least 6). The answer to the question is definitively NO. Sufficient.
Step 4 — Conclusion.
Answer: B (Statement 2 alone is sufficient)
Takeaway: In DS questions with an even number of data points, the median's sign constrains the distribution far more tightly than the sum — keep this in your toolkit for Statistics and Sets Problems questions.