GMAT Club Official Solution:During an overnight run, a server handled two types of jobs: validation jobs and migration jobs. Every validation job took the same amount of time, and every migration job took the same amount of time. If each migration job took 6 minutes longer than each validation job, what was the average (arithmetic mean) processing time per job for all the jobs handled in that run? Let the processing time for each validation job be v minutes. Then the processing time for each migration job was v + 6 minutes.
(1) The total time spent on validation jobs was three times the total time spent on migration jobs.
Let the number of validation jobs be x and the number of migration jobs be y. Then the total time spent on validation jobs was vx, and the total time spent on migration jobs was (v + 6)y. (1) gives:
vx = 3(v + 6)y
Since both the counts and v are unknown, the average processing time cannot be determined. Not sufficient.
(2) The server handled five times as many validation jobs as migration jobs.
Let the number of migration jobs be y. Then the number of validation jobs was 5y. The average processing time per job was
(5vy + (v + 6)y)/(6y) = (6v + 6)/6 = v + 1
Since v is unknown, the average processing time cannot be determined. Not sufficient.
(1)+(2) From (2), x = 5y. Substitute into (1):
5vy = 3(v + 6)y
5v = 3v + 18
v = 9
So each validation job took 9 minutes, and each migration job took 15 minutes. Using the 5:1 ratio from statement (2), the average processing time per job was:
(5 * 9 + 15)/6 = 10
Sufficient.
Answer: C.