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SharukhB



Attachment:
GMAT-Club-Forum-5aqni4h9.png

This is part of GMAT focus - test 5

Thank you! That's very helpful.
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Alan, Beth, and Chad all needed to use a printer—whose toner cartridge was running out—to print one document each. The documents comprised only text and no significant amount of blank space so the printer's software gave an accurate estimate of how many pages the cartridge could print. Based on the numbers of pages in their documents, they determined a strategy by which Chad' document and exactly one of the others would be fully printed before the cartridge ran out, with the other document having to wait until after the cartridge was replaced. Which document besides Chad's was to be printed before the cartridge replacement?

Strip the story away, and the question says this: Chad plus exactly one of Alan or Beth can be printed before the cartridge runs out. We need to know which one.

(1) If Chad's document were printed first, the cartridge would not have been able to print Alan's document.

After printing Chad, Alan still could not be fully printed. So Alan cannot be the one printed with Chad. Therefore Beth must be the one. Sufficient.

(2) Beth's document had fewer pages than Alan's document.

If Chad and Alan could both be printed, then Chad and Beth could also be printed, since Beth needs fewer pages than Alan. But the stem says Chad and exactly one of the others could be printed, not both. So Alan cannot be the one. Therefore Beth must be the one. Sufficient.

Answer: D.
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Hey Bunuel,

While eliminating option B, the logic is, since A has more pages than B therefore it is necessary that B and C are printed together not A and C. but what if the cartridge has enough ink to print A and C. In that case B has to be eliminated right?

Bunuel
Alan, Beth, and Chad all needed to use a printer—whose toner cartridge was running out—to print one document each. The documents comprised only text and no significant amount of blank space so the printer's software gave an accurate estimate of how many pages the cartridge could print. Based on the numbers of pages in their documents, they determined a strategy by which Chad' document and exactly one of the others would be fully printed before the cartridge ran out, with the other document having to wait until after the cartridge was replaced. Which document besides Chad's was to be printed before the cartridge replacement?

Strip the story away, and the question says this: Chad plus exactly one of Alan or Beth can be printed before the cartridge runs out. We need to know which one.

(1) If Chad's document were printed first, the cartridge would not have been able to print Alan's document.

After printing Chad, Alan still could not be fully printed. So Alan cannot be the one printed with Chad. Therefore Beth must be the one. Sufficient.

(2) Beth's document had fewer pages than Alan's document.

If Chad and Alan could both be printed, then Chad and Beth could also be printed, since Beth needs fewer pages than Alan. But the stem says Chad and exactly one of the others could be printed, not both. So Alan cannot be the one. Therefore Beth must be the one. Sufficient.

Answer: D.
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Hey Bunuel,

While eliminating option B, the logic is, since A has more pages than B therefore it is necessary that B and C are printed together not A and C. but what if the cartridge has enough ink to print A and C. In that case B has to be eliminated right?



Your question is not clear, and I do not really understand what you are implying there. Statement (2) is sufficient because Beth’s document has fewer pages than Alan’s, so if Chad and Alan could both be printed, then Chad and Beth could also both be printed, which contradicts the condition that Chad and exactly one of the others could be printed. Therefore, the only possible document besides Chad’s is Beth’s.
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