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Jamesk486
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as you said (2) can cleary answer the question but i think you are wrong for (1) .(1) is suff too because we know it;s about 6 teams and the rule says even*even=even , even*odd=even .
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I chose B.. Bt m thinking one thing that ..N will always b even .. Because..6 groups* X(no of persons in each group)= N .. So n will never b odd integer..

I think question shud have asked that.. THE NUMBER OF MEMBERS IN EACH GROUP IS EVEN OR ODD? then Choice B wud be No. because 18 total members will contain 3 members in each group..so 6*3= 18..

correct me if m wrong
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sanjoo

I think question shud have asked that.. THE NUMBER OF MEMBERS IN EACH GROUP IS EVEN OR ODD? then Choice B wud be No. because 18 total members will contain 3 members in each group..so 6*3= 18..

correct me if m wrong

The question asks whether n is even. n does not equal to 6*(the # of people in each group) because the # of people in each group is not necessarily the same. For example, if the # of people in 6 groups are {1, 1, 1, 1, 1, 2} then n=7=odd.

Hope it's clear.
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Jamesk486
A line of people waiting to enter a theater consists of 7 separate and successive groups. The first person in each group purchases one ticket for each person in the group and for no one else. If n is the total number of tickets sold for the first 6 groups, is n an even group?

(1) There are no more than 4 people in each group
(2) The 19th person in line purchases the tickets for the 7th group

we have to figure out the number of ticket sold (thus by logical extension the number of people in the group) ; we have to exclude the 7th group
(1) There are no more than 4 people in each group
6 group * (1 person or 2 person or 3 person or max 4 person)
total people can be 6 to 24
NOT SUFFICIENT


(2) The 19th person in line purchases the tickets for the 7th group
The beginning of 7th group is 19, so it means the end of 6th group is 18
18 is even ; so the number of people is even
SUFFICIENT
ANSWER B
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from the question we can say that there are 7 total groups
target
if n is the total number of tickets sold for the first 6 groups, is n an even group

#1
(1) There are no more than 4 people in each group

this can be yes or no as multiples of all 6 groups can be ( 5 even and 1 odd ) or all even
#2
The 19th person in line purchases the tickets for the 7th group
which means that for 6 groups total count of tickets were 18 , even
sufficient

Jamesk486
A line of people waiting to enter a theater consists of 7 separate and successive groups. The first person in each group purchases one ticket for each person in the group and for no one else. If n is the total number of tickets sold for the first 6 groups, is n an even group?

(1) There are no more than 4 people in each group
(2) The 19th person in line purchases the tickets for the 7th group


DS21246
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what do you mean by successive groups? bb Bunuel
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what do you mean by successive groups? bb Bunuel
“Successive groups” just means the groups are lined up one after another with no gaps: group 1, then group 2, then group 3, and so on until group 7.
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The is an incredibly easy question, the obvious reason why people are getting it wrong is because people are assuming that the groups are of equal size (i.e., hence the questions about how you can possibly get anything other than n being if 6 is even, since even*even = EVEN and even*odd = EVEN.
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