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C
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Difficulty:
45%
(medium)
Question Stats:
64% (01:29) correct
36%
(01:39)
wrong
based on 445
sessions
History
Date
Time
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Not Attempted Yet
14 Mar 2012, 10:56
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If x is an integer, is x even?
(1) x^2 - y^2 = 0 --> x^2=y^2 --> |x|=|y| --> x can be odd as well as even. Not sufficient.
(2) x^2 + y^2 = 18 --> clearly insufficient, for example x can 0, so even as well as 1, so odd.
(1)+(2) Add up equations: 2x^2=18 --> x^2=9 --> x=3=odd or x=-3=odd. Sufficient.
Answer: C.
(1) x^2 - y^2 = 0 --> x^2=y^2 --> |x|=|y| --> x can be odd as well as even. Not sufficient.
(2) x^2 + y^2 = 18 --> clearly insufficient, for example x can 0, so even as well as 1, so odd.
(1)+(2) Add up equations: 2x^2=18 --> x^2=9 --> x=3=odd or x=-3=odd. Sufficient.
Answer: C.
04 Jul 2021, 19:05
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We know, x is an integer and we need to find whether x is even?
Statement 1:
x^2 = y^2
|x| = |y|
‘x’ can either be even or odd. INSUFFICIENT
Statement 2:
x^2 + y^2 = 18
Here we ‘y’ can be any value, it’s not written that ‘y’ should be integer. So, INSUFFICIENT
Both statements together:
Here, we can conclude that x = 3 and y = 3. So, both together are SUFFICIENT
Answer is C
Posted from my mobile device
Statement 1:
x^2 = y^2
|x| = |y|
‘x’ can either be even or odd. INSUFFICIENT
Statement 2:
x^2 + y^2 = 18
Here we ‘y’ can be any value, it’s not written that ‘y’ should be integer. So, INSUFFICIENT
Both statements together:
Here, we can conclude that x = 3 and y = 3. So, both together are SUFFICIENT
Answer is C
Posted from my mobile device
