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lumone
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If p is a positive integer less than 29 and q is the remaind Updated on: 15 Jun 2014, 05:50
Originally posted by lumone on 03 Jun 2008, 08:51.
Last edited by Bunuel on 15 Jun 2014, 05:50, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to DS forum.
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60% (01:41) correct 40% (01:46) wrong based on 303 sessions

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If p is a positive integer less than 29 and q is the remainder when 29 is divided by p, what is the value of q?

(1) p is a two-digit number.
(2) p = 3^k, where k is a positive integer.
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B
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FN
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If p is a positive integer less than 29 and q is the remaind 03 Jun 2008, 09:28
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lumone
If p is a positive integer less than 29 and q is the remainder when 29 is divided by p, what it the value of q?

(1) p is a 2-digit number
(2) p=3^k, where k is a positive interger
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looks like B

P=29+q

p<29...

1) is clearly insuff..p=28, q=1, p=27 q=2..

2) p=3^K..

ok so P=3 or 9 27...

29/3 remainder is 2.. 29/9 remainder is 2...29/27 remainder is 2...
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If p is a positive integer less than 29 and q is the remaind 03 Jun 2008, 10:14
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lumone
If p is a positive integer less than 29 and q is the remainder when 29 is divided by p, what it the value of q?

(1) p is a 2-digit number
(2) p=3^k, where k is a positive interger
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Answer is B guys.

29/3 --> R=2

29/9 ---> R=2

29/27---> R=2
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If p is a positive integer less than 29 and q is the remaind 21 Sep 2011, 10:05
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kulki
Oh i didnt realize the type while copy pasting. the question is :
If p is a postive integer less than 29 and q is the remainder
when 29 is divided by p, what is the value of q?
(1) p is a two-digit number.
(2) p = 3^k, where k is a positive integer.
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Statement 1: p can take multiple values. q will be different in each case.
Statement 2: p can be 3/9/27. In each case, q will be 2
You can divide and see that the remainder is 2 in each case. Theoretically, you can prove that it will be so because \(29 = 3^3 + 2\)
So when 29 is divided by a power of 3 which is smaller than or equal to 3, it will completely divide \(3^3\) and remainder will always be 2. Statement 2 is sufficient alone.

Answer (B).

(It is easy to fall for (C) here to narrow down the value of p to 27. Make sure you get two different remainders before you decide that you need both statements.)
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If p is a positive integer less than 29 and q is the remaind 15 Jun 2014, 05:27
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I am getting (E).

Can someone please explain why we're not taking into consideration the possibility of 3^4 = 81 ==> just like 3^3 = 27, satisfies both statements but the remainders are different, 2 for 27 and 29 for 81!
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If p is a positive integer less than 29 and q is the remaind 15 Jun 2014, 05:53
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Mfz83
I am getting (E).

Can someone please explain why we're not taking into consideration the possibility of 3^4 = 81 ==> just like 3^3 = 27, satisfies both statements but the remainders are different, 2 for 27 and 29 for 81!
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Notice that we are told that p is a positive integer less than 29, hence it cannot be 81. The correct answer is B as explained above.
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If p is a positive integer less than 29 and q is the remaind 14 Jul 2016, 06:50
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lumone
If p is a positive integer less than 29 and q is the remainder when 29 is divided by p, what is the value of q?

(1) p is a two-digit number.
(2) p = 3^k, where k is a positive integer.
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29>p>0

(1) p is a two-digit number.
29/ 10 leaves 9 as remainder
29/11 leaves 7 as reminder
Not sufficient.

(2) p = 3^k, where k is a positive integer.
p can be 3, 9 or 27

29 divided by 3 or 9 or 27 leaves same reminder= 2

Sufficient.

B is the answer
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If p is a positive integer less than 29 and q is the remaind 19 Jun 2023, 07:18
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