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arjtryarjtry
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Is 49 in the set S? Updated on: 09 Feb 2016, 09:59
Originally posted by arjtryarjtry on 25 Jul 2008, 18:32.
Last edited by Bunuel on 09 Feb 2016, 09:59, edited 1 time in total.
Renamed the topic, edited the question and moved to DS forum.
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35% (medium)

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56% (00:48) correct 44% (00:43) wrong based on 209 sessions

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Is 49 in the set S?

(1) All numbers in set S are multiple of 7.
(2) All numbers in set S are square numbers.
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E
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rao
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Is 49 in the set S? 25 Jul 2008, 18:44
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arjtryarjtry
Is 49 in the set S?

(1) All numbers in set S are multiple of 7.
(2) All numbers in set S are square numbers.

A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient
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IMO E, 49*49 may be in the set, which is multiple of 7 and sq of 49.
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Is 49 in the set S? 25 Jul 2008, 20:06
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First there is no mention of how many numbers are there in the setS.

However, if you combine the two

You get that the if there is only one number in the set it will have to be 49 OR (49*49)

S1. Multiple of 7 S2. Squares of numbers

IMO E
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Is 49 in the set S? 25 Jul 2008, 20:18
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arjtryarjtry
Is 49 in the set S?

(1) All numbers in set S are multiple of 7.
(2) All numbers in set S are square numbers.

A. Statement (1) ALONE is sufficient but Statement (2) ALONE is not sufficient.
B. Statement (2) ALONE is sufficient but Statement (1) ALONE is not sufficient.
C. BOTH Statements TOGETHER are sufficient, but NEITHER Statement alone is sufficient.
D. Each Statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient

IMO E, 49*49 may be in the set, which is multiple of 7 and sq of 49.
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IMO E :-D
clearly
(1) does not give any range or any info : hence 49 may or may not be present => innsufficient
(2) does not mention the range => insufficient

(1) and (2) => multiple of 7 and square number => can be 7*7,7*(7*7*7) ...etc hence again range is important to be known => no unique answer => insufficient
(E) is the valid choice
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Is 49 in the set S? 26 Mar 2011, 19:49
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Pkit
damn tricky.
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The trick in the question is its wording.

(1) All numbers in set S are multiples of 7.

Here, some will read the statement and interpret it in the following way 'All multiples of 7 are in set S.' which is definitely not what is given. What is given is that every element of the set S is a multiple of 7 so as an example, S could be {7, 0, -14, 28}... every element is a multiple of 7 but the set does not have all multiples of 7.

(2) All numbers in set S are square numbers.

Exact pitfall in this statement too. Some will read the statement and interpret it in the following way 'All perfect squares are in set S.' which is definitely not what is given. What is given is that every element of the set S is a perfect square but the set does not have all perfect squares.

So people would be replying with 2 most common answers to this question - (D) the most popular incorrect answer
(E) the correct answer
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Is 49 in the set S? 15 Jul 2016, 02:10
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arjtryarjtry
Is 49 in the set S?

(1) All numbers in set S are multiple of 7.
(2) All numbers in set S are square numbers.
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(1) All numbers in set S are multiple of 7.
S={21,35} or {7,14,21,28,35,42,49,56} ==> Insufficient

(2) All numbers in set S are square numbers.
S={4,16,64,100} or {1,9,25,49,81,121} ===> Insufficient

Merging both
Our set should have (multiple of 7)\(^2\)
S={\(7^2(49),14^2,21^2\)} or {\(77^2,700^2,35^2\) }==>Still Insufficient

Answer is E
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Is 49 in the set S? 09 Sep 2019, 06:37
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could zero be in the set?
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Is 49 in the set S? 09 Sep 2019, 06:49
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ghnlrug
could zero be in the set?
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Yes, because 0 is both a multiple of 7 (0/7 = integer) and square of an integer (0 = 0^2).
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Is 49 in the set S? 24 Jul 2024, 02:44
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