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xyztroy
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On a certain fishing boat that catches tuna, wheeled carts Updated on: 07 Nov 2013, 01:17
Originally posted by xyztroy on 08 Mar 2010, 21:41.
Last edited by Bunuel on 07 Nov 2013, 01:17, edited 1 time in total.
Added the OA.
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65% (hard)

Question Stats:

50% (01:34) correct 50% (01:42) wrong based on 241 sessions

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On a certain fishing boat that catches tuna, wheeled carts are used to move the fish around the deck. If a cart can hold 1,600 lbs of fish, what is the maximum number of tuna that can be put in one cart?

(1) A tuna will slip through the net and not get caught unless it weighs over 5 lbs.

(2) A net full of tuna, which is 100 fish, weighs on average 800 lbs
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A
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On a certain fishing boat that catches tuna, wheeled carts 08 Mar 2010, 23:45
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a

min is 5 lb so 1600/5 givesn maximum
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On a certain fishing boat that catches tuna, wheeled carts 09 Mar 2010, 01:29
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IMO A ... OA pls

W = n*m where n = number of fish , m =weight of fish

n = W/m is max when m is minimum as W is constant.

Thus 1 is sufficient.


statement 2 gives average weight , does not give any indication of minimum weight of fish..Thus insufficient.
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On a certain fishing boat that catches tuna, wheeled carts 10 Mar 2010, 08:28
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OA is A...thanks for the explanation...I think I did not understand the question clearly.
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On a certain fishing boat that catches tuna, wheeled carts 10 Mar 2010, 21:27
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From equilbrium strategy, minimum of one thing needs maximum of other thing to balance.

In statement 1, the minimum weight of tuna is mentioned. So it needs maximum count of tuna to balance.

Statement 2 provides the range.

Hence A.
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On a certain fishing boat that catches tuna, wheeled carts 06 Nov 2013, 23:51
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Statement 1: We know that at minimum fish should weigh more than 5. But 5.1, 5.001, give different number of fish in the cart. Can we say that it is enough?
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On a certain fishing boat that catches tuna, wheeled carts 07 Nov 2013, 01:21
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Temurkhon
Statement 1: We know that at minimum fish should weigh more than 5. But 5.1, 5.001, give different number of fish in the cart. Can we say that it is enough?
Show more

Yes, we can.

On a certain fishing boat that catches tuna, wheeled carts are used to move the fish around the deck. If a cart can hold 1,600 lbs of fish, what is the maximum number of tuna that can be put in one cart?

(1) A tuna will slip through the net and not get caught unless it weighs over 5 lbs --> 1600/5 = 320. Since the weight must be over 5 lbs, then the maximum number of tuna that can be put in one cart is 319. Sufficient.

(2) A net full of tuna, which is 100 fish, weighs on average 800 lbs. Clearly insufficient.

Answer: A.

Hope it's clear.
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On a certain fishing boat that catches tuna, wheeled carts 11 Jan 2020, 08:35
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(1) Min. unit weight of a tuna = 5 lbs. The max number of tuna caught is 1600/5=320 nos.
SUFFICIENT

(2) 100 fish weighs on average 800 lbs, so 1600 lbs may mean 200 tunas on average. However, we don't know the exact max number of tunas (>200nos).
NOT SUFFICIENT

FINAL ANSWER IS (A)

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On a certain fishing boat that catches tuna, wheeled carts 04 Aug 2022, 10:01
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Bunuel
Temurkhon
Statement 1: We know that at minimum fish should weigh more than 5. But 5.1, 5.001, give different number of fish in the cart. Can we say that it is enough?

Yes, we can.

On a certain fishing boat that catches tuna, wheeled carts are used to move the fish around the deck. If a cart can hold 1,600 lbs of fish, what is the maximum number of tuna that can be put in one cart?

(1) A tuna will slip through the net and not get caught unless it weighs over 5 lbs --> 1600/5 = 320. Since the weight must be over 5 lbs, then the maximum number of tuna that can be put in one cart is 319. Sufficient.

(2) A net full of tuna, which is 100 fish, weighs on average 800 lbs. Clearly insufficient.

Answer: A.

Hope it's clear.
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Bunuel shouldn't we also consider the size aspect? Like what if fishes are of odd sizes & the container cannot fit 319 fishes? In that case both the statements would be insufficient.
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On a certain fishing boat that catches tuna, wheeled carts 10 Nov 2025, 13:13
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