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23 May 2010, 09:24
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
74% (01:22) correct
26%
(01:45)
wrong
based on 257
sessions
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Two trains, Q and P, are traveling on straight and parallel tracks. Q and P are traveling at different constant rates. If train Q is now 3 miles ahead of train P, in how many minutes will train Q be 6 miles ahead of train P ?
(1) Train Q is traveling at a speed of 150 mph and train P is traveling at a speed of 120 mph.
(2) Four minutes ago, train Q was 1 mile ahead of train P.
(1) Train Q is traveling at a speed of 150 mph and train P is traveling at a speed of 120 mph.
(2) Four minutes ago, train Q was 1 mile ahead of train P.
23 May 2010, 09:59
Kudos
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shekar123
It really helps if the stop watch is included in these questions
. Anyways, here is my take on this:
speed of P = v1
speed of Q = v2
Assuming they are traveling in the same direction
combined speed of P and Q = v2-v1
Distance in between them = 3 miles
Time required by train Q to be 6 miles ahead = t
Distance needed by Q = 3 miles
1) v2 = 150 ad v1 = 120
t = d/v = 3/(150-120) = 3/30 hrs = 1/10 *(60) = 6 mins
Sufficient
2) So 4 mins ago train Q was 1 mile ahead, and now it is 3 miles ahead, this means it traveled 2 miles in 4 mins
Thus, combined speed = d/4 = 2/4
v2 - v1 = 2/4 miles per minute (note it is not mph)
from this we can find t = 3/(v2 - v1) = 3*4/2 = 6 mins
Sufficient
My answer: D
